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SCORPION-xisa [38]
3 years ago
11

I need help on this question please.

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
3 0

Answer:

The ladder needs to be 26 ft long.

Step-by-step explanation:

So pythag is a^{2}+b^{2}=c^{2}

We have the height and distance from the window, so we need to find c

10^{2}+24^{2}=c^{2}

100+576= 676

\sqrt{676} = 26

You might be interested in
Y=-3x^2-6x+24
Lera25 [3.4K]
The x-intercept is the point at which the function intersects the x-axis.
For any point on the x-axis, y = 0. Thus we can plug in 0 for y and solve for x.

y=-3x^2-6x+24 \\ 0=-3x^2-6x+24

Let's split the middle on this quadratic.
To do this we need to find two numbers that add to equal -6 and multiply to equal -72. (-3 times 24)
Consider ways to multiply to get 72.
72 = 36 ×2...that's not going to work.
72 = 24 × 3
72 = 18 × 4
72 = 12 × 6...and 12 minus 6 is 6!
Let's add our signs; our numbers are -12 and 6.
Now, split the middle and factor.

0=-3x^2-12x+6x+24\\0=-3x(x+4)+6(x+4)\\0=(-3x+6)(x+4)

Now you should know that anything multiplied by zero is zero.
So any value that makes one of those factors equal zero is an x-intercept.
Solve each of these equations.

-3x+6 = 0
-3x = -6
x = 2

x+4 = 0
x = -4

Oh, and since all parabolas (graphs of quadratics) are symmetrical, our axis of symmetry will be the average between the two, which is x=-1.

Now for our y-intercepts. For any points on the y-axis, x=0, so if we plug in 0 for x and solve for y we'll get our y-intercept.

y = -3×0² - 6×0 + 24
y = 0 - 0 + 24
y = 24

What about our vertex? Well, we know it's going to line up with the axis of symmetry, so let's just plug in -1 for x.

y = -3×-1² - 6×-1 + 24
y = -3×1 -6×-1 + 24
y = -3 + 6 + 24
y = 27

Thus the vertex is (-1, 27)

The y value is not going to exceed 27, as this is a decreasing quadratic, (we already know y=24 is a possibilty) and this equation goes downwards infinitely, so our range is (-∞, 27)

As for x, well, it's sort of the input for our equation, meaning it can be whatever we want it to be. Thus the domain is (-∞, ∞)




3 0
3 years ago
Use the following steps to prove that log b(xy)- log bx+ log by.
borishaifa [10]

Answer with Step-by-step explanation:

a.x=b^p

y=b^q

Taking both sides log

log x=plog b

Using identity:logx^y=ylogx

p=\frac{logx}{log b}=log_b x

Using identity:log_x y=\frac{log y}{log x}

log y=qlog b

q=\frac{log y}{log b}=log_b y

b.xy=b^pb^q

We know that

x^a\cdot x^b=x^{a+b}

Using identity

xy=b^{p+q}

c.log_b(xy)=log_b(b^{p+q})

log_b(xy)=(p+q)log_b b

Substitute the values then we get

log_b(xy)=(log_b x+log_b y)

By using log_b b=1

Hence, log_b(xy)=log_b x+log_b y

3 0
3 years ago
The diagonals of quadrilateral EFGH intersect at D(?3,4). EFGH has vertices at E(3,7) and F(?4,5). What must be the coordinates
Katen [24]

Answer:

  G(3, 1), H(2, 3)

Step-by-step explanation:

When D is the midpoint of EG, it means ...

  D = (E + G)/2

or

  G = 2D -E = 2(3,4) -(3,7) = (2·3-3, 2·4-7) = (3, 1)

Likewise, H is ...

  H = 2D -F = 2(3,4) -(4,5) = (2·3-4, 2·4-5) = (2, 3)

5 0
4 years ago
What is the slope of the line perpendicular to the line with equation 4x-5y+13=0
motikmotik

Answer:

m = - 5/4

Step-by-step explanation:

If two lines are perpendicular, their slopes are negative reciprocals, which means that their product is -1

We can write the equation

4*x - 5*y + 13  = 0

as:      5*y  =  4*x  + 13      or    

y  = (4/5)*x  + 13        (1)

Equation (1) is the equation of a straight line in its slope point form, 4/5 is the slope, according to this  the slope of a perpendicular line is

-5/4

4 0
3 years ago
Help please<br><br> 3 + 3 + 2 x 2 x 1 = ?
kramer

3 + 3 + 2 x 2 x 1 = ?

3 + 3 = 6

2 x 2 = 4

6 + 4 = 10

10 x 1 = 10

Your answer is <u>10</u>

hope this helps!

3 0
4 years ago
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