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Varvara68 [4.7K]

3 years ago

9

Andrew can run the forty yard dash in 1/2 the time that Brett can. If the sum of the two boys' times is 16.2 seconds, how many s

econds does it take Brett to run the forty yard dash?

1 answer:

Zigmanuir [339]3 years ago

6 0

10.8 seconds for brett i’m pretty sure

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Solve for y 3x + 1/5y = 7

jarptica [38.1K]

I think it is y=35 because u multiply both sides by 5 move the variable right then the final solution is

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3 years ago

Quick anyone know the answer?

den301095 [7]

The sum of the measures of angles in all quadrangles is 360 °. Therefore:

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$m\angle D=(20x-1)^o\to m\angle D=(20\cdot4-1)^o=79^o\\\\Answer:\ B.\ 79^o$

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3 years ago

What is the value of y in the equation 5x + 2y = 20, when x = 0. 3 A) 2.5 B) 2.8 C) 9.25 D) 10.75

NemiM [27]

// Plug x into the equation

5(0.3)+2y=20
1.5+2y=20

// Subtract 1.5 from each side

2y=18.5

//Divide each side by 2

y=9.25 (C)

5 0

3 years ago

Will give brainliest if you help me

natali 33 [55]

Answer:

1120 in³

Step-by-step explanation:

The volume (V) of a cuboid is calculated as

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8 0

3 years ago

A pharmaceutical company receives large shipments of ibuprofen tablets and uses an acceptance sampling plan. This plan randomly

Keith_Richards [23]

Answer:

0.7208 = 72.08% probability that this whole shipment will be accepted.

Step-by-step explanation:

For each tablet, there are only two possible outcomes. Either it meets the required specifications, or it does not. The probability of a tablet meeting the required specifications is independent of any other tablet, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

4% rate of defects

This means that $p = 0.04$

26 tablets

This means that $n = 26$

What is the probability that this whole shipment will be accepted?

Probability that at most one tablet does not meet the specifications, which is:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

Thus

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{26,0}.(0.04)^{0}.(0.96)^{26} = 0.3460$

$P(X = 1) = C_{26,1}.(0.04)^{1}.(0.96)^{25} = 0.3748$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.3460 + 0.3748 = 0.7208$

0.7208 = 72.08% probability that this whole shipment will be accepted.

3 0

3 years ago