Answer:
See below
Step-by-step explanation:
![-[-(11-22)]=-[-(-11)]=-[11]= \large\boxed{-11}](https://tex.z-dn.net/?f=-%5B-%2811-22%29%5D%3D-%5B-%28-11%29%5D%3D-%5B11%5D%3D%20%5Clarge%5Cboxed%7B-11%7D)
![$ \left( \frac{3}{2} \right) \cdot \left(-\frac{22}{33} \right) = -\frac{66}{66}=\large\boxed{-1} $](https://tex.z-dn.net/?f=%24%20%5Cleft%28%20%5Cfrac%7B3%7D%7B2%7D%20%5Cright%29%20%5Ccdot%20%5Cleft%28-%5Cfrac%7B22%7D%7B33%7D%20%5Cright%29%20%3D%20-%5Cfrac%7B66%7D%7B66%7D%3D%5Clarge%5Cboxed%7B-1%7D%20%24)
![$\frac{4^2}{5^2}=\large\boxed{\frac{16}{25}} $](https://tex.z-dn.net/?f=%24%5Cfrac%7B4%5E2%7D%7B5%5E2%7D%3D%5Clarge%5Cboxed%7B%5Cfrac%7B16%7D%7B25%7D%7D%20%20%24)
![$-\frac{4}{3} -\frac{4}{13} = -\frac{4 \cdot 13}{3 \cdot 13} -\frac{4 \cdot 3}{13 \cdot 3} = -\frac{52}{39} -\frac{12}{39} = \large\boxed{-\frac{64}{39}} $](https://tex.z-dn.net/?f=%24-%5Cfrac%7B4%7D%7B3%7D%20-%5Cfrac%7B4%7D%7B13%7D%20%3D%20%20-%5Cfrac%7B4%20%5Ccdot%2013%7D%7B3%20%5Ccdot%2013%7D%20-%5Cfrac%7B4%20%5Ccdot%203%7D%7B13%20%5Ccdot%203%7D%20%3D%20-%5Cfrac%7B52%7D%7B39%7D%20-%5Cfrac%7B12%7D%7B39%7D%20%3D%20%5Clarge%5Cboxed%7B-%5Cfrac%7B64%7D%7B39%7D%7D%20%24)
![$\sqrt{\frac{27}{3} } =\sqrt{9} =\large\boxed{3}$](https://tex.z-dn.net/?f=%24%5Csqrt%7B%5Cfrac%7B27%7D%7B3%7D%20%7D%20%3D%5Csqrt%7B9%7D%20%3D%5Clarge%5Cboxed%7B3%7D%24)
Hello!
You first have to put the probability of him getting the bus and the train
for the first time he has a 2/3 chance of picking one
For the second time he has a 1/3 chance since he has to get the one he hasn't used yet
You multiply these together
2/3 * 1/3 = 2/9
The answer is 2/9
Hope this helps!
Answer:
560 is the area
Step-by-step explanation:
20x10 = 200 + the 30x12 = 560 comment if you need further explanation
The answer to the problem is B. $ 8704.70. The answer is derived as shown in the attached file.