Let Susan's present age be x
Now, after 7 years ( her age will become 7 +x then) she'll be 2 as old she was 3 years ago.
Her age 3 years ago must be x-3
Now according to question,
twice Her age 3 years ago = her age after 7 years
now,
2(x-3) = 7+x
2x-6 = 7+x
2x-x =7+6
x = 13
x = 13
Therefore, her age presenr age is 13 years.
Answer:
56
Step-by-step explanation:
Answer:
not statistically significant at ∝ = 0.05
Step-by-step explanation:
Sample size( n ) = 61
Average for student leader graduates to finish degree ( x') = 4.97 years
std = 1.23
Average for student body = 4.56 years
<u>Determine if the difference between the student leaders and the entire student population is statistically significant at alpha</u>
H0( null hypothesis ) : u = 4.56
Ha : u ≠ 4.56
using test statistic
test statistic ; t = ( x' - u ) / std√ n
= ( 4.97 - 4.56 ) / 1.23 √ 61
= 2.60
let ∝ = 0.05 , critical value = -2.60 + 2.60
Hence we wont fail to accept H0
This shows that the difference between the student leaders and the entire student population is not statistically significant at ∝ = 0.05
Answer:
77
Step-by-step explanation:
77 feet is the answer hope you mark me brainlyist
Answer: 2 1/2 miles
Step-by-step explanation:
To subtract fractions with different denominators (in this problem they are 10 and 5), you have to find the least common denominator or LCD (10). Then you have to multiply the numerator and the denominator of 4/5 by 2 to turn the denominator into the LCD (10).
1. So 2 4/5 turns into 2 8/10
2. Then subtract 2 8/10 from 5 3/10 to get the answer 2 1/2
