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d1i1m1o1n [39]
4 years ago
8

MnO2+ 4HCL--->MnCl2+Cl2+2H2O:

Chemistry
1 answer:
Rainbow [258]4 years ago
3 0
<span>Which reagent will be used up first? Thee answer is HCl.
We need to convert the amounts of the reactants into moles to see the limiting reactant.

48.2 g HCl ( 1 mol / 36.46 g) = 1.32 mol HCl

Since the ration is 1:4 then the limiting reactant is HCl. To react all of the MnO2 we need 3.44 mol HCl.

</span><span>How many grams of Cl2 will be produced? 
</span>We use the amount of limiting reactant since it will be used up first.

1.32 mol HCl (1 mol Cl2 / 4 mol HCl) ( 70.9 g Cl2 / 1 mol Cl2) =23.4 g CL2
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