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Rama09 [41]
3 years ago
14

Which of the following types of radiation can be shielded by a piece of paper or fabric? (3 points)

Chemistry
2 answers:
RUDIKE [14]3 years ago
7 0

Answer:

alpha rays

Explanation:

The alpha rays has the minimum penetration power.

alexdok [17]3 years ago
7 0
Alpha rays

Explanation: The Alpha rays has the minimum penetration
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Does Mg or Ne have a higher electronegativity value
elena55 [62]

Answer:

Ne

Explanation:

3 0
3 years ago
Read 2 more answers
50 points!! Brainliest if correct!!
Luda [366]

The answer is C. The answer is C because if u increase the surface area, the more reactants u will get. and if u get more The reactants will move faster. Hoped that Helped!:-)

4 0
3 years ago
Fission and fusion are alike in many ways. However, one difference is
Annette [7]

Explanation:

Fusion vs Fission

In fission, energy is gained by splitting apart heavy atoms, for example uranium, into smaller atoms such as iodine, caesium, strontium, xenon and barium, to name just a few. However, fusion is combining light atoms, for example two hydrogen isotopes, deuterium and tritium, to form the heavier helium. Both reactions release energy which, in a power plant, would be used to boil water to drive a steam generator, thus producing electricity.

4 0
3 years ago
An industrial manufacturer wants to convert 175 kg of methane into HCN. Calculate the masses of ammonia and molecular oxygen req
Tema [17]
Given:

175 kilograms of Methane (CH4) to be synthesized into Hydrogen Cyanide (HCN)

The balanced chemical equation is shown below:

2 CH4<span> + 2 NH</span>3<span> + 3 O</span>2<span> → 2 HCN + 6 H</span>2<span>O
</span>
To calculate for the masses of ammonia and oxygen needed, our basis will be 175 kg CH4.

Molar mass:
CH4 = 16 kg/kmol
NH3 = 17 kg/kmol
O2 = 32 kg/kmol

mass of NH3 = 175 kg CH4 / 16 kg/kmol * (2/2) * 17 kg/kmol 
mass of NH3 = 185.94 kg NH3 needed

mass of O2 = 175 kg CH4 / 16 kg/kmol * (3/2) * 32 kg/kmol
mass of O2 = 525 kg

mass of O = 525 kg / 32 kg/kmol * (1/2) * 16 kg/kmol
mass of O = 131.25 kg O 
4 0
4 years ago
When pcl5 solidifies it forms pcl4 cations and pcl6–anions. according to valence bond theory, what hybrid orbitals are used by p
SSSSS [86.1K]

When pcl5 solidifies it forms pcl4 cations and pcl6–anions. according to valence bond theory, hybrid orbitals that  are used by phosphorus in the pcl4 cations are one orbital of s and three orbital of p as it is sp³hydridised.

<h3>What is sp³ hybridization?</h3>

Hybridization is a process or system which specifies the shape and geometry of any element or molecule with bond angles too.

The pcl4 cation is sp³ hybridized because of the phosphorus behave as a central atom here and the 4 chloride molecules are attached with the p- orbitals to the phosphorus molecule.

Therefore, pcl4 cation  is sp³ hybridized.

Learn more about sp³ hybridization, here :

brainly.com/question/13062274

#SPJ4

5 0
2 years ago
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