There are 135 colored
candies in a small typical bag, in which in every 135 colored candies,
there are 27 blue candies.
Now, if there are 1 000 pile of colored candies, how much is the total
number of blue candies.
First, let’s identify how many 135 candies are there in 1 000 candies
=> 1 000 / 135
=> there are 7.407407…. repeating decimals.
Now, let’s multiply this by 27
=> 7.407… x 27
= 200, thus, there are 200 blue candies in 1000 pile of colored-candies.
6 and 10 are part of the 2 table so you would have 2(3x-5) thats the farthest we can factor it down :)
Answer:
a
=
146
Step-by-step explanation:
0
.
1
5
+
2
8
.
1
=
5
0
3
/
2
0
+
2
8
.
1
=
5
0
3
/2
0
=
2
1
.
9
This is a mixture problem.
Let the 9 karat gold to be mixed be x. The 18 karat would weight (200 - x). Since the total = 200g.
mass1 * karat1 + mass2*karat = total mass * total carat
Let mass1 be x g. mass 2 would be = (200 -x)
karat 1 = 9 karat 2 = 18
Total mass = 200g.
Total karat = 14.
9*x + 18*(200 -x) = 14*200
9x + 18*200 - 18*x = 14*200
18*200 + 9x - 18x = 14*200
3600 - 9x = 2800
3600 - 2800 = 9x
800 = 9x
9x = 800
x = 800/9
x ≈ 88.89
Therefore 88.89 grams of 9 karat gold must be mixed.
answer:
im not sure. what is ur question
step-by-step explanation:
