All categories

3 years ago

6⋅[(32−8)÷4+2] What is the answer to this expession?

Mathematics

1 answer:

Nimfa-mama [501]3 years ago

4 0

Answer:

Step-by-step explanation:

=6*[24/4+2]

=6*[6+2]

=6*8

=48

You might be interested in

the perimeter of a triangle is 59 in. The longest side is 11in. longer than the medium side, and the medium side is 3in longer t

Nataly_w [17]

Let the length of shortest side be - x
length of medium side - x +3
length of longest side - x +3 + 11
so , according to question
=> x + x +3 + x +3 + 11 = 59
=> x + x +x + 3 + 3 + 11 = 59
=> 3x = 59 - 17
=> 3 x = 42
=> x = 42/3
=> x = 14
Shortest side = x = 14
medium side = x + 3 = 14+3 = 17
longest side = x + 3 +11 = 14 + 3 + 11 = 28

4 0

3 years ago

HELLER HELLPPPP MEHHHH

ivolga24 [154]

Answer:

I think the answer is D.

Step-by-step explanation:

Five plus two times a number means 5 + 2n vice versa.

4 0

3 years ago

Read 2 more answers

Determine any asymptotes (Horizontal, vertical or oblique). Find holes, intercepts and state it's domain.

vesna_86 [32]

Factorize the denominator:

$\dfrac{x^2-4}{x^3+x^2-4x-4}=\dfrac{x^2-4}{x^2(x+1)-4(x+1)}=\dfrac{x^2-4}{(x^2-4)(x+1)}$

If $x\neq\pm2$ , we can cancel the factors of $x^2-4$ , which makes $x=-2$ and $x=2$ removable discontinuities that appear as holes in the plot of $g(x)$ .

We're then left with

$\dfrac1{x+1}$

which is undefined when $x=-1$ , so this is the site of a vertical asymptote.

As $x$ gets arbitrarily large in magnitude, we find

$\displaystyle\lim_{x\to-\infty}g(x)=\lim_{x\to+\infty}g(x)=0$

since the degree of the denominator (3) is greater than the degree of the numerator (2). So $y=0$ is a horizontal asymptote.

Intercepts occur where $g(x)=0$ ( $x$ -intercepts) and the value of $g(x)$ when $x=0$ ( $y$ -intercept). There are no $x$ -intercepts because $\dfrac1{x+1}$ is never 0. On the other hand,

$g(0)=\dfrac{0-4}{0+0-0-4}=1$

so there is one $y$ -intercept at (0, 1).

The domain of $g(x)$ is the set of values that $x$ can take on for which $g(x)$ exists. We've already shown that $x$ can't be -2, 2, or -1, so the domain is the set

$\{x\in\mathbb R\mid x\neq-2,x\neq-1,x\neq2\}$

8 0

3 years ago

Determine whether the following function is linear or quadratic. Identify the quadratic, linear, and constant terms. f(x)=3x(x−1

Nataliya [291]

It is quadratic, because the highest degree for x is 2, x². Expand the expression and you'll see: f(x)=3x²-3x-3x-7
simplify: f(x)=3x²-6x-7
the quadratic term is 3x², the linear term is -6x, the constant is -7

6 0

3 years ago

How many meters are there in 33 km?

s2008m [1.1K]

1000 meters make 1km. So let's compare that with the question.
1000m=1km
Y=33km
I represented the unknown with Y. Next, you have to cross and multiply. 33 will multiply 1,000 to give 33,000. And Y will multiply 1 to give Y. That will be;
Y=33,000m
33km makes 33,000m.
Hope that helped. Have a nice day

8 0

3 years ago