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Leokris [45]
3 years ago
12

INSTRUCTIONS:

Mathematics
2 answers:
Pie3 years ago
7 0

Answer:

vvyvyvvyvyvyvbbyefbbfbhvbfhvhfvhfvhfbvhfbvhfbvhfvfvbfvbfhvbfvf

Step-by-step explanation:

fvfnvfvfvhfbvbfdbvkurbghrsvrbagiwrgyq4tifdjbgiurwbgudfvbfsvbdhbfrifbeqyvbafwuvbrwuvbfausfbvkfdvyawrvefawevbrwugvtgbsfhvbcvfrvsafhvbarukvfshovfyuvbeuvbfoavbsfuygbreyghteufniuvehjtgidxvbtaegnveriusdfnjadnhguiwbfvkjeuigbwriokfjaicfdigseuifjgdgnsfuidvbrsguibtdgnpifuewngvhfsguipNV ijvnsidnhdfurhuaevawrbghwlabvyulzfsbvkhSDJvjsfdgntslvbdfjhgbfuyvfijgsdnvuierwnfliwdhpirqwnvdshlzcbaelfihvbglf

Sladkaya [172]3 years ago
4 0

Answer:

the final money balance that he has in his account is $1,730

Step-by-step explanation:

i did it alreay on edge

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Which expression is a difference of a number and a product?
zaharov [31]
Option A i believe but i dont know for sure
5 0
3 years ago
Help this one as well pls and thank you
anastassius [24]

Answer:

11x +9

Step-by-step explanation:

Add the two expressions together to get the total number of ice creams sold

8x+16 + 3x-7

Combine like terms

8x+3x + 16 -7

11x +9

3 0
2 years ago
Read 2 more answers
6.04x10 minus 3 cubed
Oksana_A [137]

Answer: .00604

Step-by-step explanation:

Hope this helps

7 0
3 years ago
One year, the population of a city was 64,000. Several years later it was 53,120. Find the percent decrease.
ohaa [14]

Answer:

17% i think

Step-by-step explanation:

4 0
2 years ago
Use matrices and elementary row to solve the following system:
LiRa [457]

I assume the first equation is supposed to be

5x-3y+2z=13

and not

5x-3x+2x=4x=13

As an augmented matrix, this system is given by

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]

Multiply through row 3 by 1/2:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]

Multiply through row 3 by 1/5:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -3(row 2) to row 1:

\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Multiply through row 1 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -2(row 1) to row 2:

\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]

Multipy through row 2 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]

The solution to the system is then

\boxed{x=1,y=-2,z=1}

5 0
3 years ago
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