Since, population of species A is represented by : 
Let us find the population of species A, at the end of week 1:
i.e., x = 1
i.e., 
i.e., 
i.e., 
Also, since population of species B is represented by : 
Let us find the population of species B, at the end of week 1:
i.e., x = 1
i.e., 
i.e., 
i.e.,
Thus, at the end of 1 week, species A and species B will have the same population.
Hence, option D is correct.
No this is not a function because 4 is used twice on the y side
You need to set it up as a fraction and make the fractions equal each other.
2/3 (2 of their books for 3 of yours)
x/18 (x amount of their books for 18 of yours)
(2/3)=(x/18)
multiply both sides by 18
and you get
36/3 which reduces to 12
so your answer is 12
So its a fraction all you would do is divide 96 by 64 and you would 1 and one half
Recall that the PDF is given by the derivative of the CDF:
The mean is given by
![\mathbb E[X]=\displaystyle\int_{-\infty}^\infty x\,f_X(x)\,\mathrm dx=\int_0^2\left(x-\dfrac{x^2}2\right)\,\mathrm dx=\frac23](https://tex.z-dn.net/?f=%5Cmathbb%20E%5BX%5D%3D%5Cdisplaystyle%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty%20x%5C%2Cf_X%28x%29%5C%2C%5Cmathrm%20dx%3D%5Cint_0%5E2%5Cleft%28x-%5Cdfrac%7Bx%5E2%7D2%5Cright%29%5C%2C%5Cmathrm%20dx%3D%5Cfrac23)
The median is the number
such that
. We have
but both roots can't be medians. As a matter of fact, the median must satisfy
, so we take the solution with the negative root. So
is the median.
