Question

Suppose the side length of square A is 6 inches, and the side length of square B is 9 inches. What is the area of square C if the three squares create a right triangle? A 15 in B 54 in? C 108 in? D 117 in

Answer 1

Answer:

sss

Step-by-step explanation:

sss

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Answer 2

Answer:

D.117 square in

Step-by-step explanation:

We are given that

Side length of square A=6 in

Side length of square B=9 in

We have to find the area of square C if the tree squares create a right triangle.

By using Pythagoras theorem

$(hypotenuse)^2=(Base)^2+(Perpendicular\;side)^2$

Side of square C

$(Hypotenuse)^2=6^2+9^2$

$(Hypotenuse)^2=117$

$Hypotenuse=\sqrt{117}$

Now,

The area of square C=$(side)^2$

The area of square C=$(\sqrt{117})^2=117 in^2$

Option D is true.