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HACTEHA [7]
2 years ago
14

Simplify. 1/4(1−2/3)^2+1/3

Mathematics
1 answer:
ad-work [718]2 years ago
3 0

Answer:

13/36

Step-by-step explanation:

1 - 2/3 equals 1/3 which is inside the parenthesis

square the number in parenthesis (1/3) and it equals 1/9

multiply the 2 fractions 1/4 and 1/9 to get 1/36

finally add 1/3 with 1/36

12/36 + 1/36 would equal 13/36

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Evaluate the infinite sum:
satela [25.4K]

Consider the <em>k</em>-th partial sum,

S_k = 1 + \dfrac2\pi + \dfrac3{\pi^2} + \cdots + \dfrac k{\pi^{k-1}}

More compactly,

\displaystyle S_k = \sum_{i=1}^k \frac i{\pi^{i-1}} = \frac{(1-\pi)k+\pi^{k+1}-\pi}{(1-\pi)^2\pi^{k-1}}

(this is just another case of a similar sum you asked about a while ago [24494877])

The infinite sum is the limit of the partial sum as <em>k</em> goes to infinity. We have

\displaystyle \lim_{k\to\infty} \frac{(1-\pi)k+\pi^{k+1}-\pi}{(1-\pi)^2\pi^{k-1}} = \frac\pi{(1-\pi)^2} \lim_{k\to\infty} \left(\frac{(1-\pi)k}{\pi^k} + \pi - \frac1{\pi^{k-1}} \right) = \boxed{\frac{\pi^2}{(1-\pi)^2}}

since the non-constant terms in the limit converge to 0.

Alternatively, recall that for |<em>x</em>| < 1, we have

\dfrac1{1-x} = \displaystyle \sum_{n=0}^\infty x^n

Differentiating both sides gives

\dfrac1{(1-x)^2} = \displaystyle \sum_{n=0}^\infty nx^{n-1} = \sum_{n=1}^\infty nx^{n-1}

also valid for |<em>x</em>| < 1. Take <em>x</em> = 1/<em>π</em> and you get the sum you want to compute.

5 0
2 years ago
HELP! What is the answer? (NO EXPLANATION NEEDED!)
Iteru [2.4K]
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6 0
3 years ago
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saw5 [17]
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8 0
3 years ago
Which translation maps the vertex fo the gtaph of the function f(x)=x2 onto the vertex of the function g(x)=-8x+x2+7?
dexar [7]

Answer:

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The vertex of the graph of the function g(x) = -8x + x^2 + 7 is 4 units to the right and 9 units down of the vertex of the graph of the function f(x) = x^2.

Step-by-step explanation:

4 0
2 years ago
A stack of 4 identical books is 6.28 high. What is the heigh of 30 of these books?
ziro4ka [17]

Answer:<u>47.1</u>

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8 0
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