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2 years ago

Laura walked 6 1/2 laps of a circular path in 2 hours. At that rate, how many laps of the

Mathematics

1 answer:

NARA [144]2 years ago

6 0

Answer:

3.25 in one hour

Step-by-step explanation:

6.5 ÷ 2 = 3.25

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A = 5bc<br> b = -4 and c = -3<br> Work out the value of a.

Misha Larkins [42]

Step-by-step explanation:

a=5*-4*-3

a=-2

hope this helps

4 0

2 years ago

What one is going slower

ddd [48]

Car A is going slower

8 0

2 years ago

Read 2 more answers

SOMEONE PLEASE HELP!!! HURRY

MAXImum [283]

Answer:

Slope of the line DV = -1

Step-by-step explanation:

Let point D (-5, 1) be $(x_{1}, y_{1})$

Let point V (-1, -3) be $(x_{2}, y_{2})$

$m=\frac{y_2-y_1}{x_2-x_1}$

Plug in the appropriate values,

$m = \frac{-3-1}{-1-(-5)} = \frac{-4}{4} = -1$

slope equals -1

4 0

2 years ago

300-7 [4 (3+5)]+3 to the 3rd power

Allisa [31]

The expression to solve is the
300-7 [4 (3+5)] + 3 to the 3rd power
3 to the third power means 3³, so
300-7 [4(3+5)]+3³
= 300 - 7 [4(8)] + 27
= 300 - 7[32] + 27
= 300 - 224 + 27
= 76 + 27
= 103
so, by solving this we get 103

4 0

3 years ago

A football team has a probability of .75 of winning when playing any of the other four teams in its conference. If the games are

Alexeev081 [22]

Answer:

0.3164 = 31.64% probability the team wins all its conference games

Step-by-step explanation:

For each conference game, there are only two possible outcomes. Either the team wins it, or they lose. The probability of winning a game is independent of any other game. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A football team has a probability of .75 of winning when playing any of the other four teams in its conference.

The probability means that $p = 0.75$ , and four games means that $n = 4$

If the games are independent, what is the probability the team wins all its conference games?

This is P(X = 4). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{4,4}.(0.75)^{4}.(0.25)^{0} = 0.3164$

0.3164 = 31.64% probability the team wins all its conference games

4 0

3 years ago