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2 years ago

Find the distance from the point (1, 0, -2) to the origin.

Mathematics

2 answers:

VladimirAG [237]2 years ago

6 0

Answer:

Step-by-step explanation:

NNADVOKAT [17]2 years ago

4 0

Point = P (1, 0, -2)

Origin= 0 (0, 0, 0)

The distance formula in 3D = √(n2 - n1)² + (y2 - y1)² + (Z2 - Z1)²

= √(1 - 0)² + (0 - 0)² + (-2 - 0)²

= √1 + 4

= √5

<h3>How do you find the distance from a point to the origin?</h3>

As a special case of the distance formulation, think we need to recognize the distance of a point (x,y) to the beginning. in step with the gap formula, this is √(x−0)2+(y−0)2=√x2+y2. A point (x,y) is at a distance r from the starting place if and simplest if √x2+y2=r, or, if we square each aspect: x2+y2=r2.

Conclusion: The method to find the distance among the two factors is commonly given with the aid of d=√((x2 – x1)² + (y2 – y1)²). This formula is used to find the gap among any two factors on a coordinate aircraft or x-y plane.

Learn more about distance formulation here brainly.com/question/1872885

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370 College freshmen were interviewed. 200 were registered for an Advanced Math class. 270 were registered for an English class

frozen [14]

Answer:

Step-by-step explanation:

To aid in understanding, draw three circles...

100 were registered for both Math and English.

50 were registered for both Sport and English but not Math.

70 were registered for Math, Sport, and English.

From here we will be able to calculate for those that signed up for only English class: Total number of students that signed up for english class

a. none signed up only for Maths (refer to attached document)

b. How many signed up for neither Math nor English meaning they signed up for only sports which is 70 from the venn diagram in the attachment.

c. How many signed up for an English class and at least one other class?

From the venn diagram:

we could have an English class and maths class - 100

we could also have an a English class and sports - 50

Thus total is 150.

d. What is the total fee for all the students enrolled in classes

From the diagram, 120 (english only and sport only) enrolled for only one class = 120 x $100 = $12,000

From the diagram, 180 (english and sport, maths and sport and english and maths) enrolled for two classes = 180 x $150 = $27,000

From the diagram, only 70 enrolled for the three classes = 70 x $200 = $14,000

Total fees = $12,000 + $27,000 + $14,000 = $53,000

5 0

3 years ago

Dalton when to high school at 11 yrs and 3 months he left high school at 18 yrs and 2 months old how long did Dalton spend in hi

Tanya [424]

Answer:

Dalton spent 6 years and 11 months in high school.

Step-by-step explanation:

Dalton were in high school at the age = 11 years and 3 months He left high school at the age = 18 years and 2 months

Time spent by Dalton in high school = 18 years 2 months - 11 years and 3 months

= (18 - 11) years and (2 - 3) months

= 7 years - 1 month

= (6 + 1) years - 1 month

= 6 years + 1 year - 1 month

= 6years + 12 months - 1 month

= 6 years + 11 months

Therefore, Dalton spent 6 years and 11 months in high school.

6 0

3 years ago

What are the roots to<br> the equation<br> 2x² + 6x-1=0?

lys-0071 [83]

Answer:

The roots of equations are as m = $\frac{-3}{2} + \frac{\sqrt{11} }{2}$ And n = $\frac{-3}{2} - \frac{\sqrt{11} }{2}$

Step-by-step explanation:

The given quadratic equation is 2 x² + 6 x - 1 = 0

This equation is in form of a x² + b x + c = 0

Let the roots of the equation are ( m , n )

Now , sum of roots = $\frac{ - b}{a}$

And products of roots = $\frac{c}{a}$

So, m + n = $\frac{ - 6}{2}$ = - 3

And m × n = $\frac{ - 1}{2}$

Or, (m - n)² = (m + n)² - 4mn

Or, (m - n)² = (-3)² - 4 ( $\frac{ - 1}{2}$ )

Or, (m - n)² = 9 + 2 = 11

I.e m - n = $\sqrt{11}$

Again m + n = - 3 And m - n = $\sqrt{11}$

Solving this two equation

(m + n) + ( m - n) = - 3 + $\sqrt{11}$

I.e 2 m = - 3 + $\sqrt{11}$

Or, m = $\frac{-3}{2} + \frac{\sqrt{11} }{2}$

Similarly n = $\frac{-3}{2} - \frac{\sqrt{11} }{2}$

Hence the roots of equations are as m = $\frac{-3}{2} + \frac{\sqrt{11} }{2}$ And n = $\frac{-3}{2} - \frac{\sqrt{11} }{2}$ Answer

6 0

3 years ago

Plz help me NOW I will mark you brainliest

puteri [66]

Let x be the percentage of p.
Therefore,
$m\% \: \: of \: \: n = x\% \: \: of \: \: p \\ = > \frac{mn}{100} = \frac{px}{100} \\ = > mn = \frac{px}{100} \times 100 \\ = > mn = px \\ = > \frac{mn}{p} = x$

<u>Answer:</u>

Hope you could get an idea from here.

Doubt clarification - use comment section.

8 0

2 years ago

Solve plssszzzzagavagsg

julia-pushkina [17]

Answer:

OOO I KNO ITS 7.2 15.6 OK

Step-by-step explanation:

SO WHAT YOU DO IS 7.2 THEN ROUND SO THEN ITS 6 THEN 15.6 16

THEN YOU WILL DIVIDE. I HOPE THIS HELPS

THIS IS HOW I LEARNED BUT I COULD BE WRONG.

PLZZZ BRAINLYIST!!!!

OH AND HAVE A WONDER FULL DAY

3 0

2 years ago