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Darina [25.2K]
3 years ago
11

Pals fast what are amplitude, period, phase shift and midline for f(x)=-4 cos (3x-pi)+2

Mathematics
1 answer:
GREYUIT [131]3 years ago
8 0

Answer:

amplitude = |-4| =4

period = 2 pi/3

phase shift = pi / 3

midline = 2

Step-by-step explanation:

f(x)=-4 cos (3x-pi)+2

The equation is in the form

f(x) = a cos (bx -c) +d  where |a| is the amplitude

period  is 2 pi /b

phase shift:  c/b

midline = d

amplitude = |-4| =4

period = 2 pi/3

phase shift = pi / 3

midline = 2

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2 years ago
Suppose the radius of a circle is 3 units what is the circumference
HACTEHA [7]

Answer:

6\pi or approximately 18.85 units

Step-by-step explanation:

The formula for finding the circumference of a circle is C=2\pi r, where C = circumference and r = radius. In this case, r=3, so after plugging that into C=2\pi r, we get:

C=2\pi r\\  = 2*\pi *3\\=6\pi

Since \pi is approximately 3.1415, 6\pi =6*3.1415=18.849, which rounds to 18.85. Therefore, the circumference of the circle is 6\pi, or approximately 18.85 units. Hope this helps!

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3 years ago
Can someone help me
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\sf\dfrac{4}{7}\times\dfrac{1}{6}\rightarrow\dfrac{4\times 1}{7\times 6}\rightarrow\dfrac{4}{42}\rightarrow\dfrac{2}{21}

To find out which one is bigger, we need a common denominator. The LCM of 7 and 21 is 21, so convert the first fraction into a denominator of 21. 7 goes into 21 three times, multiply this to the numerator and denominator:

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Now just compare the numerators to see which one is bigger.

\sf\dfrac{3}{21}>\dfrac{2}{21} therefore, \sf\dfrac{4}{7}\times\dfrac{1}{4}>\dfrac{4}{7}\times\dfrac{1}{6}
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3 years ago
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ZanzabumX [31]

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Step-by-step explanation:

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8 0
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