Answer:
dang I forgot how to solve this but it has something to do with 360
Step-by-step explanation:
Answer:
16 dimes and 1 nickel
23 nickel and 1 dime
These are just two you have so many options, just mess with it
Answer:
Step-by-step explanation:
so to find the equation tangent to the curve x^2+1 at the point (1,2)
-First we must find the derivative then plug in the point
d/d(x)=2x (power rule)
so then we plug in the x and y values (we don't need to worry about the 2-y value- because we did not need to compute and derivatives with y)
so we plug in 1 for the x
y=2(1)
2
now we plug it into equation of a line
y - 2 = 2(x - 1)
or
y=2x
Answer:
D
Step-by-step explanation:
p +/- [z + sqrt(pq/n)]
0.65 + [1.645 × sqrt[0.65 × (1-0.65) ÷ 50]
0.65 +/- 0 1109613165
[0.5390386835 , 0.7609613165]
Answer:
second option
Step-by-step explanation:
Given
f(x) = 
The denominator cannot be zero as this would make f(x) undefined.
Equating the denominator to zero and solving gives the value that x cannot be, that is
3x - 5 = 0 ⇒ 3x = 5 ⇒ x = 
← excluded value
Thus domain is
(- ∞, ) u (, ∞ )
