Question

Write an equation for the line parallel to the line 5/8x−7/6y =2 through the point (7,−1).

Answer 1

$y = - \frac{28}{48x - 15} - \frac{125}{321}$is the answer.

Step-by-step explanation:

For this question,

• First, find the slope of the line parallel to the line 5/8x−7/6y=2 :-

$m = - \frac{28}{ - 15 + 48x}$

•Second, find the equation of the line,

$y = - \frac{28}{48x - 15} - \frac{125}{321}$