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3 years ago

Please please please help

Mathematics

1 answer:

Simora [160]3 years ago

8 0

Answer:

a S(-3) = 2(-3)(-3)+5(-3)-12

=18-15-12

=-9

b 2x2+5x-12=0

2x2+8x-3x-12=0

2x(x-4)-3(x+4)=0

(2x-3)(x+4)=0

2x-3=0

x=3/2

x=-4

sorry I couldn't answer the other question

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Luis is a professional musician.He needs to

Deffense [45]

Step-by-step explanation:

The following prices for the same make and model used guitar for his work are :

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4 years ago

Find x so that x, X +2, X'+3 are the first three terms of a geometric sequence. Then find the 5" term of the

velikii [3]

Answer:

The fifth term is -1/4.

Step-by-step explanation:

We know that the first three terms of the geometric sequence is x, x + 2, and x + 3.

So, our first term is x.

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$x+2=xr$

And our third term will be our first term multiplied by the common ratio r twice. Therefore:

$x+3=xr^2$

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Substitute this into the third equation:

$\displaystyle x+3=x\Big(\frac{x+2}{x}\Big)^2$

Square:

$\displaystyle x+3 = x\Big( \frac{(x+2)^2}{x^2} \Big)$

Simplify:

$\displaystyle x+3=\frac{(x+2)^2}{x}$

We can multiply both sides by x:

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Expand:

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Isolate the x:

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Hence, our first term is:

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Then our common ratio r is:

$\displaystyle r=\frac{(-4)+2}{-4}=\frac{-2}{-4}=\frac{1}{2}$

So, our first term is -4 and our common ratio is 1/2.

Then our sequence will be -4, -2, -1, -1/2, -1/4.

You can verify that the first three terms indeed follow the pattern of x, x + 2, and x + 3.

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4 years ago

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Answer:

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Step-by-step explanation:

The question is mixed up. The only clear question is:

Given:

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Required

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