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Nastasia [14]
3 years ago
9

Find the slope of the line that passes through the points (-4,3) and (-2,1)

Mathematics
1 answer:
Tasya [4]3 years ago
3 0

Answer:

-2/2

Step-by-step explanation:

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Can Someone help me with this problem?
igor_vitrenko [27]
If the temperature is the same in Farenheit and Celsius, the variable F is equal to the variable C in the equation. Thus, you'll just need to replace one or both variables in the original equation and solve for the single variable. I'll just use x as the variable here:

F = 1.8C + 32
x = 1.8x + 32

subtract x from both sides

0 = 0.8x + 32

subtract 32 from both sides

-32 = 0.8x

divide both sides by 0.8

-40 = x

So, since we know x = -40 degrees, we also know that F = -40° and C = -40° too.
5 0
3 years ago
In the digram GH bisects FGI what is the answer for C.
zhannawk [14.2K]

The line GH bisects The triangle FGI meaning it divides it into two equal parts <em>(that is the definition if bisection); </em>therefore, the angles FGH and HGI are equal:

3x-2=4x-13

Now let us add 2 to both sides gives

3x=4x-11

subtracting 4x from both sides gives

-x=-11x=11.

Hence, x = 11.

The measure of FGH is

3x-2=3(11)-2=31

(B)

The measure of HGI is

4x-13=4(11)-13=31

(C)

The measure of FGI is the sum of HGI and FGH:

\begin{gathered} \text{FGI}=\text{HGI}+\text{FGH}=31+31 \\ FGI=62^o \end{gathered}

<em />

7 0
1 year ago
) In a right triangle, a and b are the lengths of the legs and c is the length of the
Dima020 [189]

Answer:

  6.3 mm

Step-by-step explanation:

The Pythagorean theorem tells you ...

  c^2 = a^2 + b^2

Solving for "a", you get

  a = √(c^2 -b^2)

  a = √(8.3^2 -5.4^2) = √39.73

  a ≈ 6.3 . . . . mm

The length of "a" is about 6.3 mm.

7 0
3 years ago
Read 2 more answers
Please help me with this, Thank you
lesya [120]

Answer:

y = \frac{6}{5}

Step-by-step explanation:

Given

6 | 5y - 1 | - 1 = 29 ( add 1 to both sides )

6 | 5y - 1 | = 30 ( divide both sides by 6 )

| 5y - 1 | = 5

The absolute value function always returns a positive value. However, the expression inside can be positive or negative, thus

5y - 1 = 5 ( add 1 to both sides )

5y = 6 ( divide both sides by 5 )

y = \frac{6}{5}

OR

- (5y - 1) = 5, that is

- 5y + 5 = 5 ( subtract 5 from both sides )

5y = 0 ⇒ y = 0

As a check substitute these values into the left side and if equal to the right side then they are the solutions.

x = 0 : 6|0 - 1 | - 1 = 6 | - 1| - 1 = 6(1) - 1 = 6 - 1 = 5 ≠ 29

x = \frac{6}{5} : 6 | 6 - 1 | - 1 = 6(5) - 1 = 30 - 1 = 29

Thus x = \frac{6}{5} is a solution, x = 0 is extraneous

5 0
3 years ago
How to count fast from 82-199
boyakko [2]
Just skipppppp counttttt
3 0
3 years ago
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