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Alina [70]
3 years ago
14

Find the circum center of a triangle whose vertices are (-2, -1) , (-1, 6 ) and (2, 7).​

Mathematics
1 answer:
lina2011 [118]3 years ago
7 0

Answer:

(-1/3; 4)

Step-by-step explanation:

(-2, -1) , (-1, 6 ) and (2, 7).​

x=(-2-1+2)/3= -1/3

y=(-1+6+7)/3=12/3=4

=> (-1/3; 4)

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Lilit [14]
There are 2, 3/4 in 2
5 0
3 years ago
Read 2 more answers
If 2a/4=b/4 and b≠0, what does 5b equal in terms of a?
dedylja [7]

Step-by-step explanation:

you must have made a typo here.

none of the answer options are correct for the given problem.

let me just show you what you told me, and how I can solve at least this :

2a/4 = b/4

this simply means (multiply both sides by 4) :

2a = b

so, 5b is then (multiplying both sides by 5) :

5×2a = 5b

10a = 5b

but again, "10a" is not among the offered answers.

so, I don't know if you made a mistake with the basic problem or with the answer options.

8 0
1 year ago
Which if the following items showed the greatest percentage in bulk
Katyanochek1 [597]
No image shown but just remember that percentage is out of 100

0.03 is 3%
7 0
2 years ago
During the last ten years oliver has played 1200 games of chess oliver has drawn 6% of the games he has lost 33% of the game cal
Anna [14]

Answer:

6+33=39 now we subtract from 100

100-39=61

He won 61 percent of the games

now we multiply 1200*0.61=732

so he won 732 of the 1200 games

Hope This Helps!!

6 0
2 years ago
Given sin thata = 2/5 and 0° < thata < 90°. find sin 2 thata​
Andrej [43]

Recall the double angle identity:

\sin2\theta=2\sin\theta\cos\theta

With \theta measuring between 0º and 90º, we know \cos\theta>0. So from the Pythagorean identity, we get

\sin^2\theta+\cos^2\theta=1\implies\cos\theta=\sqrt{1-\sin^2\theta}=\dfrac{\sqrt{21}}5

Then

\sin2\theta=2\dfrac25\dfrac{\sqrt{21}}5=\dfrac{4\sqrt{21}}{25}

5 0
3 years ago
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