It would be C) y = ( x + 1 ) ( x - 3 ) ( x - 2 ) because when you graph the points it falls to the left and rises to the right.
Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60
t=1
The 15 lbs at $7=$105
So multiple 5x9 as a test and check results. 105-45=60
Here you can see that 60 is a factor of 6 by 10 so you got lucky and got the answer of 10lbs at $6 & 5lbs at $9=15 lbs at $7 average
Answer:
y -8 = -5(x -6)
Step-by-step explanation:
The point-slope form of the equation for a line is generally written ...
y -k = m(x -h)
for slope m and point (h, k).
The slope of your parallel line is the same as the slope of the reference line, -5. So your equation is ...
y -8 = -5(x -6)