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1 year ago

Points m is the midpoint of FG. Can you determine the value of a?

Mathematics

1 answer:

GenaCL600 [577]1 year ago

6 0

Using the midpoint concept, it is found that the value of a is of a = 2.

<h3>What are the coordinates of the points?</h3>

Researching this problem on a search engine, the coordinates are given as follows:

F(b + 1, a + 2).

M(3,5).

(2a, 3b+3).

<h3>What is the midpoint concept?</h3>

The midpoint between two points is the halfway point between them, and is found using the mean of the coordinates.

Hence the following system of equations can be built:

(b + 1 + 2a)/2 = 3.

b + 1 + 2a = 6.

b = 5 - 2a.

(a + 2 + 3b + 3)/2 = 5

a + 3b + 5 = 10

a + 3b = 5.

Since b = 5 - 2a, we have that:

a + 15 - 6a = 5.

5a = 10

a = 10/5

a = 2.

The value of a is of a = 2.

More can be learned about the mid-point concept at brainly.com/question/10956693

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Given the arithmetic sequence an = 4 − 3(n − 1), what is the domain for n? All integers where n ≥ 1 All integers where n > 1

krok68 [10]

All integers where n ≥ 1.

We have given that the sequence,

$a_{n} =4-3(n-1)$

We have to find the domain for n.

<h3>What is the meaning of arithmetic sequence?</h3>

Arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant. Difference here means the second minus the first.

That is, $a_{n} =a+(n-1)d$

where a = first term of sequence.

d =common difference.

n =number of terms which belongs to natural numbers

By the definition of arithmetic sequence n starts with 1

Remember that,the natural number starts with 1

Now, in given sequence for nth term

$a_{n} =4-3(n-1)$

The domain for n is All integers where n ≥ 1.

To learn more about the arithmetic sequence visit:

brainly.com/question/20118982

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2 years ago

A club has 10 members.

TEA [102]

That is the combination of 10 over 3, which is calculated as the quotient of factorials:
n!/k!(n-k)!
where n = 10 and k = 3:
= 10!/3!(10 - 3)!
= 10!/3!*7!
= (10*9*8)/(3*2*1)
= 720/6
= 120
therefore there a re 120 possible different groups

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3 years ago

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