I have 1 hundreds, 4 ones, 2 tens, and 1 tenths. What number am I?
2 answers:
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Answer:
the parabola can be written as:
f(x) = y = a*x^2 + b*x + c
first step.
find the vertex at:
x = -b/2a
the vertex will be the point (-b/2a, f(-b/2a))
now, if a is positive, then the arms of the parabola go up, if a is negative, the arms of the parabola go down.
The next step is to see if we have real roots by using the Bhaskara's equation:
Now, draw the vertex, after that draw the values of the roots in the x-axis, and now conect the points with the general draw of the parabola.
If you do not have any real roots, you can feed into the parabola some different values of x around the vertex
for example at:
x = (-b/2a) + 1 and x = (-b/2a) - 1
those two values should give the same value of y, and now you can connect the vertex with those two points.
If you want a more exact drawing, you can add more points (like x = (-b/2a) + 3 and x = (-b/2a) - 3) and connect them, as more points you add, the best sketch you will have.
Answer:
5
Step-by-step explanation:
(3,8) (0,4)
X1 = 3 X2 = 0
Y1 = 8 Y2 = 4
Do what's in the parentheses so...
- 3-0= 3
- 8-4= 4
Now plug it in!
Now you are going to finish the parentheses so...
- (3)^2= 9
- (4)^2= 16
Plug that in so that you have this...
Add 9+16 to get...
Then you are going to find the number or numbers that make this a perfect square...
So 5 is your answer