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3 years ago

Which one do i pick?

Mathematics

2 answers:

den301095 [7]3 years ago

7 0

Answer:

ASA

Step-by-step explanation:

angle b = angle a (given) (A)

since ab bisects cd, ae = eb (S)

angle ceb = angle aed (vertically opp angles) (A)

Nuetrik [128]3 years ago

3 0

Answer:

ASA

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

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mrs_skeptik [129]

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3 years ago

Read 2 more answers

Write an absolute value equation for the graph shown below

BabaBlast [244]

So, hmmm keeping in mind that, an absolute value expression is in effect a piece-wise function, let's find its "slopes", the negarive slope on the left-side and the positive slope on the right side, and let's use the vertex point as our first point

what is the slope of a line that passes through (2, -1) and (0,7)

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 2}}\quad ,&{{ -1}})\quad 
% (c,d)
&({{ 0}}\quad ,&{{ 7}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{7-(-1)}{0-2}\implies \cfrac{7+1}{-2}\implies -4
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-1)=-4(x-2)
\\\\\\
\boxed{y+1=-4(x-2)}$

now, what is the slope of a line that passes through (2, -1) and (4,7)

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 2}}\quad ,&{{ -1}})\quad 
% (c,d)
&({{ 4}}\quad ,&{{ 7}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{7-(-1)}{4-2}\implies \cfrac{7+1}{2}\implies 4
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-1)=4(x-2)
\\\\\\
\boxed{y+1=4(x-2)}$

since an absolute value expression is just a piece-wise with a +/- versions, then we can just combine those two.

$\bf \begin{cases}
y+1=-4(x-2)\\
y+1=4(x-2)
\end{cases}\implies y+1=\pm 4(x-2)
\\\\\\
y+1=|4(x-2)|\implies y=|4(x-2)|-1$

7 0

3 years ago