To solve the problem above, we will be using the equation in solving the surface area of a cylinder which goes. A = 2pi r^2 + 2pi r h, A is for the surface area, pi is 3.1416; h is the height and r is the radius. Basing on this formula the radius will be 0.3982 ft both top and bottom.
Answer:
Step-by-step explanation:
y=-3/2x+5
Answer:
50
Step-by-step explanation:
Because of supplementary angles that line has to equal to 180
180-75 = 105
so 105 = (2x + 5)
you can subtract 5 from each side and get
100 = (2x)
then divide each side by 2 and you get
x = 50
you can check it by doing (2 x 50 + 5)
2 x 50 = 100 + 5 = 105 + 75 = 180
<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>D</em><em>.</em>
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>
Polygon HJKL has vertices H(-3, 4), J(2, 6), K(2, 1), and L(-3, -1). What are the slopes of sides HJ, JK, KL, and LH and how wou
aleksklad [387]
<span> the slopes of sides HJ, JK, KL, and LH and how would you classify HJKL?</span>