Question

Please help me with 1,2,3,4,5,6 please

Answer 1

Answer:

1.

${h}^{2} = {p }^{2} + {b}^{2}$

${13}^{2} \: = {12}^{2} + {b}^{2}$

${b}^{2} = {13}^{2} - {12}^{2}$

${b }^{2} = 169 - 144$

${b}^{2} = 25/tex] [tex]b = \sqrt{25}$

$b = 5$

hope this helps you all of your question's is base on the formula given above

mark me as brainliest pls

Answer 2

Answer:

all of these are right angled triangle. so u can use pythagoras theorem, h²=p²+b²

longest side is called hypotenious (h)

and u can assume any of the remaining side as p and b as your choice

eg=

1) h=13

p=12

b=?

using pythagrous theroem

h²=p²+b²

13²=12²+b²

169= 144+b²

169-144=b²

25=b²

25 is the square root of 5 so

5²=b²

square root of each side will be cancelled so

b = 5

In this way u can solve your questione.....