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makvit [3.9K]
3 years ago
9

CAN SOMEONE PLEASE HELP ME WITH THIS GEOMETRY QUESTION THANK YOU !!!

Mathematics
1 answer:
Neko [114]3 years ago
3 0

Answer:

y=20\sqrt{1}

Step-by-step explanation:

The construction of the figure gives us three right triangles, where we can apply Pythagora's Theorem.

I have added two variables to the image in the picture attached.

On the triangle with sides y,h,16 we have:

y^2-16^2=h^2

On the triangle with sides h,z,25 we have:

z^2-25^2=h^2

Equating h^2:

y^2-16^2=z^2-25^2\qquad\qquad [1]

On the bigger triangle with sides y,z,16+25=41 we have:

y^2+z^2=41^2

Adding this last equation with [1]:

y^2-16^2+y^2+z^2=z^2-25^2+41^2

Simplifying:

2y^2-16^2=41^2-25^2

Operating:

2y^2-256=1681-625

2y^2=1056-256

2y^2=800

Dividing by 2:

y^2=400

Taking square root:

y=20

To enter the number in the required format:

\boxed{y=20\sqrt{1}}

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Answer:

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2 years ago
Use the zero product property to find the solutions to the equation 2x2 + x-1 = 2
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Answer:

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Step-by-step explanation:

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