All categories

3 years ago

NEED HELP ASAP !!!!!!!

2 answers:

8 0

Selection C is appropriate.

_____
C = (2A+B)/3 = (2(-3, 6) +(6, -3))/3 = (0, 3).
D is the same thing, but with the coordinates swapped, hence (3, 0).

maria [59]3 years ago

8 0

The selection of c is the best answer given

You might be interested in

The coordinates of point A are (p, q) and coordinates of point B are (p+2q, q+2p). Provide your complete solutions and proofs in

Dafna1 [17]

Answer:

The mid-point (p + q , q + p) of AB is the same distance from the x-axis and the y-axis

Step-by-step explanation:

* Lets explain how to solve the problem

- Any point will be equidistant from the x-axis and the y-axis must have

equal coordinates

- Ex: point (4 , 4) is the same distance from the x-axis and the y-axis

because the distance from the x-axis to the point is 4 (y-coordinate)

and the distance from the y-axis and the point is 4 (x-coordinate)

- If (x , y) is the mid-point of a segment its endpoints are

$(x_{1},y_{1})$ and $(x_{2},y_{2})$ , then

$x=\frac{x_{1}+x_{2}}{2}$ and $y=\frac{y_{1}+y_{2}}{2}$

* Lets solve the problem

∵ Point A has coordinates (p , q)

∵ Point B has coordinates (p + 2q , q + 2p)

- The mid-point of AB is (x , y)

∵ $x=\frac{p+p+2q}{2}$

∴ $x=\frac{2p+2q}{2}$

- Take 2 as a common factor from the terms of the numerator

∴ $x=\frac{2(p+q)}{2}$

- Divide up and down by 2

∴ x = p + q

∵ $y=\frac{q+q+2p}{2}$

∴ $y=\frac{2q+2p}{2}$

- Take 2 as a common factor from the terms of the numerator

∴ $y=\frac{2(q+p)}{2}$

- Divide up and down by 2

∴ y = q + p

∴ The mid point of AB is (p + q , q + p)

- p + q is the same with q + p

∵ The x-coordinate of the mid point of AB is p + q

∵ The y-coordinate of the mid point of AB is q + p

∵ p + q = q + p

∴ The coordinates of the mid-point of AB are equal

- According the explanation above

∴ The mid-point (p + q , q + p) of AB is the same distance from the

x-axis and the y-axis

8 0

3 years ago

What’s 5(x+12) equal

juin [17]

Multiply using the distributive property so it would be 5x+60

7 0

3 years ago

a photo album contains small and large photographs. Each large photograph has side lengths that are twice the side lengths of ea

zysi [14]

Take the area of the small photograph and divide it by four, assuming it's a square, each side would then be 6 inches. The large photograph has double the side length of the small one, so 6 multiplied by 2 is 12. To find the area of the large (square) photograph, multiply 12 by 12 as two of the sides, and the area of the large photo is 144 square inches

4 0

3 years ago

Read 2 more answers

Pyramid A is a right square pyramid with a height of 100 m and a square base with a perimeter of 356 m. Pyramid B has a square b

Tomtit [17]

Answer:

The volume of pyramid B is 3.5 times greater than the volume of pyramid A

Step-by-step explanation:

The area of squared based a pyramid is given by:

$Area = \frac{1}{3}*s*s*h$