Question

Solve for f. d = 16ef² f=±4de‾‾‾√ f=±4de√e f=±de√4e f=±de√16

Answer 1

Answer:

The value of f out of given expression $d=16ef^2$ is $\frac{\pm 1}{4}\sqrt{\frac{d}{e}}$

Step-by-step explanation:

Given : expression $d=16ef^2$

We have to solve for f.

Consider the given expression  $d=16ef^2$

Divide both side by 16e, we get,

$\frac{d}{16e}=f^2$

Now, taking square root, both sides, we have,

$\sqrt{\frac{d}{16e}}=\sqrt{f^2}$

Simplify, we get,

$\sqrt{\frac{d}{16e}}=f$

We know $\sqrt{16}=\pm 4$ , we get,

$\frac{\pm 1}{4}\sqrt{\frac{d}{e}}=f$

Thus, The value of f out of given expression $d=16ef^2$ is $\frac{\pm 1}{4}\sqrt{\frac{d}{e}}$

Answer 2

Answer: $f=\pm \frac{\sqrt{de}}{4e}$

Step-by-step explanation:

Here, the given expression is,

$d=16ef^2$

or $16ef^2=d$

$\implies f^2 =\frac{d}{16e}$

$\implies f=\pm\sqrt{\frac{d}{16e}}$

$\implies f =\pm \frac{\sqrt{d}}{4\sqrt{e}}$

$\implies f= \pm \frac{\sqrt{de}}{4e}$  ( By rationalization )

Which is the required value of f.