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son4ous [18]
3 years ago
14

What is a real world example of rate of change

Mathematics
1 answer:
Tatiana [17]3 years ago
3 0

Answer:

Step-by-step explanation:

A population of rats increasing by 40 rats per week. A car traveling 68 miles per hour  

distance traveled changes by 68 miles each hour as time passes)

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-10x - 135 = 117 + 2x<br><br> A. -18<br><br> B. 22<br><br> C. 25<br><br> D. -21
Mice21 [21]

la respuesta que encontré yo fue la c

5 0
3 years ago
Zachery is solving the equation 3/4 (x - 8) = 12
Maru [420]

Answer:

3/4*x - 3/4*8=12

3/4x -6=12

3/4x=12+6

3/4x=18

x=24

Step-by-step explanation:

multiply 3/4 into the content inside the brackets

have -3/4*8 cross the equal sign changing its sign from - to +

divide both sides by 3/4

6 0
3 years ago
What is m angle ABC​
victus00 [196]

Answer:

3rd option: 60 degrees

Step-by-step explanation:

We can see in the diagram that the angle on C is a supplementary angle, which means that the sum of 135 and internal angle will be equal to 180 degrees.

Let x be the internal angle,

Then

x+135 = 180

x = 180-135

x = 45 degrees

So now we know that two interior angles of the triangle.

Also we know that sum of all internal angles of triangle is 180 degrees.

Using the same postulate:

A+B+C = 180

75 + B + 45 = 180

120+B = 180

B = 180 - 120

B = 60 degrees

So,

third option is the correct answer ..

6 0
3 years ago
Read 2 more answers
A box contains 3 coins. One coin has 2 heads and the other two are fair. A coin is chosen at random from the box and flipped. If
Blababa [14]

Answer: Our required probability is \dfrac{1}{2}

Step-by-step explanation:

Since we have given that

Number of coins = 3

Number of coin has 2 heads = 1

Number of fair coins = 2

Probability of getting one of the coin among 3 = \dfrac{1}{3}

So, Probability of getting head from fair coin = \dfrac{1}{2}

Probability of getting head from baised coin = 1

Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

\dfrac{\dfrac{1}{3}\times 1}{\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times 1}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{3}}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\\\\=\dfrac{1}{2}

Hence, our required probability is \dfrac{1}{2}

No, the answer is not \dfrac{1}{3}

5 0
3 years ago
Use distributive property to remove the parentheses. Simplify your answer as much as possible please.
slavikrds [6]

Answer:

  28y^3 -35y^5

Step-by-step explanation:

  = 7y^3(4) -7y^3(5y^2)

  = 28y^3 -35y^5

_____

The applicable rule of exponents is ...

  (y^a)(y^b) = y^(a+b)

7 0
2 years ago
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