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Mice21 [21]
3 years ago
14

Suppose that y varies directly with x and y = 10 when x = 20. What is y when x = 15?

Mathematics
1 answer:
tresset_1 [31]3 years ago
5 0

Answer: y = 7.5

Step-by-step explanation:

Suppose that y varies directly with x

That is, y∝x

Convert y∝x to a full equation by introducing a constant k to the right hand side.

Therefore, y = kx

Given that y = 10 and x = 20

Substitute y and x in the equation above. We have;

10 = k(20)

10 = 20k

20k = 10

k = 10/20

k = 0.5

Since k = 0.5, the equation y = kx becomes y = 0.5x

Now, to find y if x = 15, substitute x in equation y = 0.5x

Therefore, y = 0.5(15)

y = 7.5

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200,000+ 70,000+ 7,000+ 100+ 80
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Cross multiply to get answer<br> x + 5/10 = 2x-3/15
Andreyy89

Once cross multiplied you end up with this:

15x+75=20x−30

Next subtract 20x from both sides.

15x+75−20x=20x−30−20x

−5x+75=−30 -----------> Answer

Now subtract 75 from both sides

−5x+75−75=−30−75

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Now divide by -5 on both sides.

-5/-5x = -105/-5

<h3 /><h3>x = 21 --------------> ANSWER</h3>
3 0
3 years ago
four 3 megawatt wind turbines can supply enough electricity to power 3000 homes. How many turbines would be required to power 55
fiasKO [112]

Answer:

The number of turbines is 74

Step-by-step explanation:

* Lets explain how to solve the problem

- Four 3 megawatt wind turbines can supply enough electricity

 to power 3000 homes

∴ The number of turbines is 4

∵ Each turbine give 3 megawatt

∴ The four turbines give ⇒ 4 × 3 = 12 megawatt

- This quantity give enough electricity to power 3000 homes

∴ The number of homes for the 12 megawatt is 3000

- We need to find how many turbines can cover enough electricity

  to power 55,000 homes, so we must to know the quantity of

  electricity that be enough to power 55,000 homes

* <em>Lets use the cross multiplication to solve the problem</em>

∵         megawatt    :     number of homes

                  12          :              3,000

                  ?            :            55,000

- <em>By using cross multiplication</em>

∴ ?=\frac{(55,000)(12)}{3,000}=\frac{660,000}{3000}=220

∴ The enough electricity to power 3000 homes = 220 megawatt

∵ Each turbine gives 3 megawatt

- Find the number of turbines divides the total megawatt by the the

  megawatt of one turbine

∴ The number of turbines = 220 ÷ 3 = 73.3

- If we take 73 only the electricity will not be enough to cover all

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∴ The number of turbines is 74

5 0
3 years ago
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levacccp [35]
It is A, 1/5 hopefully i am the BRAINLIEST!!!!!
6 0
2 years ago
Read 2 more answers
today's local newspaper lists 20 stocks of local interest. of those stocks ten increased five decreased and five remained unchan
coldgirl [10]

Answer:

P(x=2) = 0.2368

Step-by-step explanation:

given data

stocks of local interest N = 20

stocks increased K = 10

stocks decreased =  5

remained unchanged = 5

solution

we take here no of stock that are increased randomly n = 2

so here Hypergeometric random variable can take integer value

{max(0, n+k - N ), min(n,K) } = {0,2}

so here

P(x=2)

so

P(x=k)  = \frac{(^K_k)\times (^{N-K}_{n-k}) }{(^N_n)}      .......................1

P(x=2 ) = \frac{(^{10}_2)\times (^{20-10}_{2-2}) }{(^{20}_2)}    

solve it we get

P(x=2 ) = 0.236842

now we use excel function as

HYPGEOM.DIST (k,n,N.cumulative)   .....................2

so it will be

HYPGEOM.DIST (2,2,10,,false)

we get

HYPGEOM.DIST (2,2,10,,false)  = 0.236842

so

P(x=2) = 0.2368

4 0
3 years ago
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