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mixer [17]
3 years ago
12

Complete the explanation to determine whether each statement is always, sometimes, or never true. If quadrilateral PQRS is a rho

mbus and one diagonal has a slope of 4, then the other diagonal has a slope of
1/4 .
The diagonals of a rhombus are , so the product of the slopes of the diagonals is . Therefore, the diagonals of a rhombus have slopes of 4 and
1/4 , since 4 · 1/4 −1. The statement is true.
Mathematics
1 answer:
dimaraw [331]3 years ago
4 0

Answer:

True I believe

Step-by-step explanation:

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PLEASE HELP ME PLEASE??
BigorU [14]

Answer:

Table A is correct

Step-by-step explanation:

All you have to do is multiply the hours by 5 to get the answer.

Table B is adding not multiplying.

<em>Can I please have BRAINLIEST?</em>

4 0
3 years ago
A line is parallel to y=3x +8 and intersects the point (-3,7). What is the equation of this parallel line?
RoseWind [281]

Answer:

y=3x

Step-by-step explanation:

7 0
3 years ago
Question 1 of 15<br> Solve 18x+62 12x+18.<br> A. x ≥ 4<br> B. x≤ 4<br> C. x≤2<br> D. x ≥ 2
Alborosie

Answer:

18+62=80x

12+18=30x

x=80÷30=2

x>2

4 0
2 years ago
Alex and Freddy collect stamps. The number of stamps in Alex’s collection is in ratio 3:5 to the number of stamps in Freddy’s co
Tems11 [23]
Suppose Alex has 3x stamps, Freddy has 5x stamps. After Freddy gives Alex 10 stamps, Alex has 3x+10 while Freddy has 5x-10
the new ratio is 7 to 9, so we have the equation: (3x+10)/(5x-10)=7/9
9(3x+10)=7(5x-10)
27x+90=35x-70
160=8x
x=20
So Alex has 3*20=60 stamps while Freddy has 5*20=100. Together they have 160
4 0
3 years ago
You are studying the relationship between the history of early childhood trauma (categorized as trauma/no trauma) and weight in
jeka57 [31]

Answer:

You can decide to <u>reject</u> the Null Hypothesis at p < 0.05.

Step-by-step explanation:

In this case, the relationship between the history of early childhood trauma and weight in adulthood are being studied.

The categories of childhood trauma are:

Trauma and No trauma.

So, number of rows is, <em>r</em> = 2.

The categories of weight in adulthood are:

Low to normal, Overweight, and Obese

So, number of columns is, <em>c</em> = 3.

The distribution of the statistic \chi^{2} is chi-square with (<em>r </em>- 1)(<em>c </em>- 1) degrees of freedom, where <em>r</em> represents the number of rows in the two-way table and <em>c</em> represents the number of columns.

Compute the degrees of freedom as follows:

df = (r-1)(c-1)=(2-1) \times (3-1) = 2

It is provided that the calculated value of Chi-square test statistic is 18.26.

Compute the <em>p</em>-value of the test as follows:

p-value=P(\chi^{2}_{2}\geq 18.26)\\=0.000108\\\approx0.00011

Decision rule:

The null hypothesis will be rejected if the <em>p</em>-value of the test is less than the significance level.

The significance level is, <em>α</em> = 0.05.

<em>p</em>-value = 0.00011 < <em>α</em> = 0.05.

The null hypothesis will be rejected at 5% level of significance.

Thus, the complete statement is:

"You can decide to <u>reject</u> the Null Hypothesis at p < 0.05."

4 0
3 years ago
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