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Natalija [7]
4 years ago
5

Larissa invested $19,000 in an eleven-year CD giving 7.5% interest, but needed to withdraw $2,500 after four years. If the CD’s

penalty for early withdrawal was one year’s worth of interest on the amount withdrawn, how much money did Larissa have when the CD reached maturity, not including the amount she withdrew?
a.
$13,612.50
b.
$30,675.00
c.
$30,112.50
d.
$14,175.00
Mathematics
2 answers:
Arte-miy333 [17]4 years ago
7 0

The answer would be B!

antoniya [11.8K]4 years ago
6 0
Larissa invested $19,000 in an eleven-year CD giving 7.5% interest, but needed to withdraw $2,500 after four years. If the CD’s penalty for earlywithdrawal was one year’s worth of interest on the amount withdrawn, how much money did Larissa have when the CD reached maturity, not including the amount she withdrew 
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Ugo [173]

Answer:

y=-3.2\\\\y=-2.2\\\\y=-1.8

Step-by-step explanation:

Insert the given x values for the given equation to find the corresponding y coordinate:

y=0.2x-2

x:-6,-1,1

Insert -6:

y=0.2(-6)-2

Simplify multiplication (when multiplying a negative and a positive, the result will always be negative):

y=-1.2-2

Simplify (when subtracting from a negative number, add the values, but keep the negative symbol):

y=-3.2

Insert -1:

y=0.2(-1)-2\\\\y=-0.2-2\\\\y=-2.2

Insert 1:

y=0.2(1)-2\\\\y=0.2-2\\\\y=-1.8

:Done

3 0
3 years ago
Verify the identity. 4 csc 2x = 2 csc2x tan x
vlada-n [284]

Step-by-step explanation:

4csc(2x) = 2csc^2(x) tan(x)

We start with Left hand side

We know that csc(x) = 1/ sin(x)

So csc(2x) is replaced by 1/sin(2x)

4 \frac{1}{sin(2x)}

Also we use identity

sin(2x) = 2 sin(x) cos(x)

4 \frac{1}{2sin(x)cos(x)}

4 divide by 2 is 2

Now we multiply top and bottom by sin(x) because we need tan(x) in our answer

2\frac{1*sin(x)}{sin(x)cos(x)*sin(x)}

2\frac{sin(x)}{sin^2(x)cos(x)}

2\frac{1}{sin^2(x)} \frac{sin(x)}{cos(x)}

We know that sinx/ cosx = tan(x)

Also  1/ sin(x)= csc(x)

so it becomes 2csc^2(x) tan(x) , Right hand side

Hence verified



6 0
3 years ago
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Sphinxa [80]
For a single payment with compound interest, the equation to use is F=P(1+i)^n where F is the value after n periods, P is the present value, and i is the interest rate.

If we want the final value F to double in 5 years, F is then equal to P then n=5. The equation is now:

2P=P(1+i)^5
2=(1+i)^5
i=14.87% per year
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kozerog [31]

Step-by-step explanation:

if a+3=5 then

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