Using the simple spinner below what is the probability of landing on either 2, 4, or 7?
2 answers:
You might be interested in
<span>The difference between two integers is at most 16
x1 - big integer
x2- small integer
</span><span>the smaller integer is 12
so
x2 = 12
substitution
</span>
<span>
solve for x1
however, note the fact larger
thus meaning
x1 > x2 applies to this problem
</span>
x1 - big integer
x2- small integer
</span><span>the smaller integer is 12
so
x2 = 12
substitution
</span>
<span>
solve for x1
however, note the fact larger
thus meaning
x1 > x2 applies to this problem
</span>
Answer:
20.823 nautical miles
S20°E
Step-by-step explanation:
I assume you mean ° (degrees), not ' (minutes). There are 60 minutes in 1 degree.
S52°E means "south, 52° east", or 52° east of south.
S50°W means "south, 50° west", or 50° west of south.
1 knots = 1 nautical mile / hour, so the boat first travels 8 nautical miles from A to B, then 4.5 nautical miles from B to C, then finally back to A.
If we say A is at the origin, then the coordinates of B are:
(8 sin 52°, -8 cos 52°)
And the coordinates of C are:
(8 sin 52° − 4.5 sin 50°, -8 cos 52° − 4.5 cos 50°)
(2.857, -7.818)
So the distance from A to C is:
x = √(2.857² + (-7.818)²)
x ≈ 8.323
And the total distance of the race is:
d = 8 + 4.5 + 8.323
d = 20.823
The compass bearing from A to C is:
θ = atan(2.857 / 7.818)
θ ≈ S20°E
Answer:
120°; 240°
Step-by-step explanation:
Let's first solve for :
At this point it's just a matter of drawing a circle, and mark where the angle is(please excuse my paint skills, but free hand drawing would be even worse). Red line, is
on the cosines, and both the green and blue lines are valid solutions. The green line is a quarter of a circle, plus 30°, or 120°. The blue one is 3/4 of a circle, minus 30 degrees, or 240°.
