A hospital uses 218 liters of blood in a week.

Convert 467.03 to scientific notation

nikitadnepr [17]

Answer:

4.6703 x 10^2

3 0

3 years ago

Determine which point is the solution to the given system.

KatRina [158]

Answer:

D

Step-by-step explanation:

We equate both the y's and solve for x algebraically:

$-\frac{4}{7}x+16=-\frac{2}{7}x+12\\16-12=-\frac{2}{7}x+\frac{4}{7}x\\4=\frac{2}{7}x\\x=\frac{4}{\frac{2}{7}}\\x=14$

Now taking the value x= 14 and putting it in the 1st equation would give us y:

$y=-\frac{4}{7}x+16\\y=-\frac{4}{7}(14)+16\\y=8$

Hence the solution is (14,8), answer is D

7 0

4 years ago

Playland park charges 7 dollars admission plus 75 crnts per ride. Funland park charges 12.50$ admission plus 50 cents per ride.

WINSTONCH [101]

Answer:

22 rides

Step-by-step explanation:

Both the parks has a fixed cost (admission fee) and a variable cost (per ride cost). We can model 2 equations in "x" [let x be number of rides], equate them and find "x".

Playland Park:

Fixed Cost = 7

Variable Cost = 0.75x (in dollars)

Equation = 7 + 0.75x

Funland Park:

Fixed Cost = 12.50

Variable Cost = 0.50x (in dollars)

Equation = 12.50 + 0.50x

Now we equate and solve for x:

$7+0.75x=12.50 + 0.50x\\0.75x-0.50x=12.50-7\\0.25x=5.50\\x=\frac{5.50}{0.25}\\x=22$

Hence,

the cost would be same for both parks for 22 rides

8 0

3 years ago

What is the length of AC ? 3ft 4ft 9ft 18ft

WINSTONCH [101]

ΔACB and ΔMNB are similar. Therefore the corresponding sides are in proportion:

$\dfrac{AC}{MN}=\dfrac{CB}{NB}\\\\MN=9\ ft\\CB=2\cdot3\ ft=6\ ft\\NB=3\ ft$

Substitute:

$\dfrac{AC}{9}=\dfrac{6}{3}\\\\\dfrac{AC}{9}=2\ \ \ \ |\cdot9\\\\AC=18\ ft$

5 0

3 years ago

Plzzz I need help with this question I tried to solve it many times but I can't

blsea [12.9K]

Answer and Step-by-step explanation: Area of a right triangle, (as any other triangle), is calculated as: $A1=\frac{(base)(height)}{2}$

Area of a rectangle is calculated as: $A2=(side)(side)$

Area of a right trapezoid is: $A3=\frac{(a+b)h}{2}$ , where:

a is short base

b is long base

h is height

1) Expressing areas in terms of x:

Area of triangle S1:

$S1=\frac{(2x-3)(4x-6)}{2}$

$S1=4x^{2}-12x+9$

Area of rectangle S2:

$S2 = (4x-6)(3x-2)$

$S2=12x^{2}-26x+12$

Area of trapezoid S3:

$S3=\frac{(2x+3+4x+1)(2x-3)}{2}$

$S3=\frac{(6x+4)(2x-3)}{2}$

$S3=6x^{2}-5x-6$

2) a) $S=4x^{2}-12x+9+12x^{2}-26x+12-(6x^{2}-5x-6)$

$S=4x^{2}-12x+9+12x^{2}-26x+12-6x^{2}+5x+6$

$S=10x^{2}-33x+37$

Which is the same as S = (2x-3)(5x-9)

b) For the areas to be the same:

$\frac{(3x-2+3x-2+2x-3)(4x-6)}{2}=\frac{(6x+4)(2x-3)}{2}$

$\frac{(8x-7)(4x-6)}{2}=\frac{(6x+4)(2x-3)}{2}$

$32x^{2}-48x-28x+42=12x^{2}+8x-18x-12$

$20x^{2}-66x+54=0$

Using Bhaskara to solve the second degree equation:

$\frac{66+\sqrt{(-66)^{2}-(4.20.54)} }{2(20)}$

$x_{1}=\frac{66+6}{40}$ = 1.8

$x_{2}=\frac{66-6}{40}$ = 1.5

For the areas of AFGC and ADEB to be equal, x has to be 1.5 or 1.8.

c) Expand a polynomial (or equation) is to multiply all the terms, remiving the parenthesis. Reduce a polynomial (or equation) is to combine terms alike,e.g.:

$S=(2x-3)(5x-9)$