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Write a division expression with a quotient that is: greater than 8÷0.001 less than 8÷0.001 between 8÷0.001 and 8÷110 does one b

Anna71 [15]

Answer:

9÷0.001 is greater than 8÷0.001.

7÷0.001 is less than 8÷0.001.

8÷0.002 lie between 8÷0.001 and 8÷110.

Step-by-step explanation:

The division expression which is greater than 8÷0.001 is:

9÷0.001

Since, the numerator of the number 9÷0.001 is greater than 8÷0.001. and as their denominator is same.

so, the number whose numerator is greater than the other will result in the overall number to be greater.

The division expression which is less than 8÷0.001 is 7÷0.001.

Since, for two numbers with same denominator the number whose numerator is smaller is smaller than the other.

The division expression that lie between 8÷0.001 and 8÷110 is: 8÷0.002.

Since 8÷0.002 is greater than 8÷110, as for two numbers with same numerator but different denominator the number whose denominator is greater is a smaller number.

similarly 8÷0.002 is smaller than 8÷0.001.

8 0

3 years ago

HELP PLEASE! What does it mean if the probability is 20% that a spinner will stop in a red section? (I think it's C.)

Svetradugi [14.3K]

80% not stop on red so the answer would be c for that

8 0

4 years ago

In each of the following data sets, tell whether the outlier seems certain to be due to an error or whether it could conceivably

emmasim [6.3K]

Answer:

a) There is outlier (lower category), but this outlier seem certain to be due to an error.

b) There is outlier (upper category), this outlier seem certain to be conceivably correct.

Step-by-step explanation:

a) The outlier in the rock weight is certain to be due to an error. As shown, the rock was weighed five time to ascertain the actual weight or perhaps to known the mean weight. <em>Thus, having a value 4.91 can not be true. It can only be due to an error of recording the values.</em> It suppose to be recorded as 49.1.

b) Since this was a sample of annual income of five different families, it quite possible that a particular family annual income is $1, 200, 000. Hence, we cannot regard this outlier an error, rather conceivably true.

See attached for the box plot of the two data sets.