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MrRissso [65]
2 years ago
6

When you have two shapes to compare on a coordinate plane, you can determine the scale factor, knowing that the transformation w

as a dilation. Generate instructions you would give another student to determine the scale factor. If you know the center of dilation is the origin, you can simply divide any non-zero coordinate of the transformed figure by the corresponding coordinate of the original figure to get the scale factor. Sample Response: Locate two corresponding ordered pairs of the two shapes. Calculate how much the pre-image values were multiplied by to obtain the image values. This is your scale factor. You can calculate this by dividing the coordinates of the mage by the corresponding coordinates of the pre-image. Which did you include in your response? Check all that apply. Use corresponding ordered pairs. Divide the coordinates of the image by the pre-image. Determine that the pre-image times the scale factor produces the image.
Mathematics
1 answer:
Svet_ta [14]2 years ago
6 0

Answer:

babylonia asyria and south merica this

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marissa [1.9K]

Answer:

R3 Theorem: If parallel lines are cut by a transversal, then alternate interior angles are congruent.

R4 Theorem: Congruence of segments is reflexive.

S5 ΔABC ≅ ΔCDA

7 0
2 years ago
If you reflect (–2, –8) across both axes, which quadrant will it be in? Justify your reasoning.
stepan [7]
The quadrant would be the first one, because once reflected over the y-axis, it would become (2,-8), and once reflected over the x-axis, it would become (2,8)
8 0
3 years ago
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Please help solve this SAT math problem. I have 4 more like these so need help with this so that I can solve the rest by myself.
stealth61 [152]

The notation just means

(f/g)(-4) = f(-4) / g(-4)

If f(x) = x² + 2 and g(x) = 1 - 3x, then

f(-4) = (-4)² + 2 = 16 + 2 = 18

g(-4) = 1 - 3 (-4) = 1 + 12 = 13

and so

(f/g)(-4) = 18/13

8 0
2 years ago
Please help this is my last one
stiks02 [169]

Answer:

(4,1)

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below :)

6 0
3 years ago
X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y
andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}

Part b.

Consider V(3X + 2Y)

\begin{aligned}V(3 X+2 Y) &=3^{2} V(X)+2^{2} V(Y) \\&=(9)(5)+(4)(8) \\&=77\end{aligned}

Part c.

Consider P(3X + 2Y < 18)

A normal random variable is also linear combination of two independent normal random variables.

3 X+2 Y \sim N(18,77)

Thus,

P(3 X+2 Y < 18)=0.5

Part d.

Consider P(3X + 2Y < 28)

Z=\frac{(3 X+2 Y-18)}{\sqrt{77}}

\begin{aligned} P(3X + 2Y < 28)&=P\left(\frac{3 X+2 Y-18}{\sqrt{77}} < \frac{28-18}{\sqrt{77}}\right) \\&=P(Z < 1.14) \\&=0.8729\end{aligned}

Therefore, the values for the given normal random variables are found.

To know more about the normal random variables, here

brainly.com/question/23836881

#SPJ4

The correct question is-

X and Y are independent, normal random variables with E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8. Determine the following:

a. E(3X + 2Y)

b. V(3X + 2Y)

c. P(3X + 2Y < 18)

d. P(3X + 2Y < 28)

8 0
1 year ago
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