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MrRissso [65]
3 years ago
6

When you have two shapes to compare on a coordinate plane, you can determine the scale factor, knowing that the transformation w

as a dilation. Generate instructions you would give another student to determine the scale factor. If you know the center of dilation is the origin, you can simply divide any non-zero coordinate of the transformed figure by the corresponding coordinate of the original figure to get the scale factor. Sample Response: Locate two corresponding ordered pairs of the two shapes. Calculate how much the pre-image values were multiplied by to obtain the image values. This is your scale factor. You can calculate this by dividing the coordinates of the mage by the corresponding coordinates of the pre-image. Which did you include in your response? Check all that apply. Use corresponding ordered pairs. Divide the coordinates of the image by the pre-image. Determine that the pre-image times the scale factor produces the image.
Mathematics
1 answer:
Svet_ta [14]3 years ago
6 0

Answer:

babylonia asyria and south merica this

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2(x + 4) − 1 = 2x + 7
Margarita [4]

Answer:

All real numbers are solutions to this problem.

Step-by-step explanation:

I) Simplify:

2(x + 4) - 1 = 2x + 7

x + 4 - 0.5 = x + 3.5 (Divide by 2)

x + 3.5 = x + 3.5 (Simplify <em>x + 4 - 0.5</em>)

x = x

II) Conclusion:

Any real number will work as a solution.

7 0
3 years ago
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Warren’s tape measure is marked in increments of 1/16 inch, not in decimal numbers. To measure the tiles, he needs to know the s
Ilya [14]

Answer:

2 4/16th

realistically, it would be 2 1/4, which is the same thung

5 0
3 years ago
The original quantity is 10 and the new quantity is 13. What is the percent change?​
Leya [2.2K]

3 is 13 more than 10, and 3 is 30% of 10, so 30% im pretty sure

6 0
3 years ago
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Can someone please help with this because I don’t understand if and I’ve tried most answers
irina1246 [14]

Answer:

The width measures 2.5 cm

Step-by-step explanation:

Area of triangle = Area of rectangle

1/2 bh = wh

1/2(5)(6) = w(6)

1/2(30) = 6w

15 = 6w

15 ÷ 6 = w

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5 0
4 years ago
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Solve Q²= a(p²-b²)/p in form of y=mx+c
umka2103 [35]

Answer:

We want to rewrite:

q^2 = a*(p^2 - b^2)/p

as a linear equation, in the form:

y = m*x + c

So we start with:

q^2 = a*(p^2 - b^2)/p

we can expand the left side to get:

q^2 = (a/p)*p^2 - (a/p)*b^2

q^2 = a*p - (a/p)*b^2

Now we can ust define:

a*p = c

Then we can replace that to get:

q^2 = -(a/p)*b^2 + c

now we can replace:

q^2 = y

b^2 = x

Replacing these, we get:

y = -(a/p)*x + c

finally, we can replace:

-(a/p) = m

then we got the equation:

y = m*x + c

where:

y = q^2

x = b^2

c = a*p

m = -(a/p)

4 0
3 years ago
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