NEED HELP ASAP IM FAILING AND I NEED HELP WITH THIS QUESTION

Mathematics

2 answers:

Leno4ka [110]3 years ago

6 0

Answer:

because 6 was already in the problem, therefore, it would’ve had to been x

Step-by-step explanation:

Illusion [34]3 years ago

6 0

6 was already in the problem so it’s already x i believe

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Find the centroid for an area defined by the equations y = x² + 3 and y = - (x – 2)² + 7

meriva

The points where the 2 graphs intersect is where x = 0 and x = 2.

- 2 2
x = INT x dA / INT dA
0 0

INT dA = INT -x^2 + 4x + 3 - (x^2 + 3 ) dx = INT -2x^2 + 4x
= -2 x^3/3 + 2x^2
= 2.667 between 0 and 2

xdA = -2x^3 + 4x^2 INT xdA = -x^4/2 + 4x^3/3 = 2.667

centroid = 2.667 / 2.667 = 1 (x = 1)

3 0

4 years ago

Read 2 more answers

Solve the system of equations by graphing: 2x + 3y = 2 6x + 18y = 9

cluponka [151]

The answer is A: x=1/2 , y= 1/3

Solve the following system:
{2 x + 3 y = 2 | (equation 1)
{6 x + 18 y = 9 | (equation 2)

Swap equation 1 with equation 2:
{6 x + 18 y = 9 | (equation 1)
{2 x + 3 y = 2 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:
{6 x + 18 y = 9 | (equation 1)
{0 x - 3 y = -1 | (equation 2)

Divide equation 1 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x - 3 y = -1 | (equation 2)

Multiply equation 2 by -1:
{2 x + 6 y = 3 | (equation 1)
{0 x+3 y = 1 | (equation 2)

Divide equation 2 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x+y = 1/3 | (equation 2)

Subtract 6 × (equation 2) from equation 1:
{2 x+0 y = 1 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Divide equation 1 by 2:
{x+0 y = 1/2 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Collect results:
Answer: {x = 1/2, y = 1/3