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3 years ago

Why is it important for the leading coefficient to be nonzero?

Mathematics

1 answer:

kipiarov [429]3 years ago

4 0

Answer:

Because if it is zero, then it is multiplied the variable and it will be zero. For example if I had 0x(squared) + x, it would just be x because zero times any number is zero. Looking at the problem, I would assume it was quadratic because it had x squared, but it isn't because there are 0 x squared values.

Step-by-step explanation:

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Please help! Thank you

Temka [501]

Answer:

b. the radio of feet to inches

4 0

3 years ago

for the following questions, determine how many solutions each equation has. if one solution, state the value of x. x+6+8=2x-x+1

vichka [17]

Answer:

infinite solutions

Step-by-step explanation:

x+6+8=2x-x+14

x+6+8=x+14

x+14=x+14

14=14

x=x

plug in any number

2+6+8=2(2)-2+14

16=16

another example

8+6+8=2(8)-8=14

22=22

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3 years ago

6√18 + 3√50 simply ?

-BARSIC- [3]

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3 years ago

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3 years ago

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It is believed that Lake Tahoe Community College (LTCC) Intermediate Algebra students get less than seven hours of sleep per nig

Kitty [74]

Answer: No , at 0.05 level of significance , we have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

Step-by-step explanation:

Let $\mu$ denotes the average hours of sleep per night.

As per given , we have

$H_0:\mu=7\\H_a:\mu$

, since $H_a$ is left-tailed and population standard deviation is unknown, so the test is a left-tailed t -test.

Also , it is given that ,

Sample size : n= 22

Sample mean : $\overline{x}=7.24$

Sample standard deviation : s= 1.93

Test statistic : $t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}$

i.e. $t=\dfrac{7.24-7}{\dfrac{1.93}{\sqrt{22}}}\approx0.58$

For significance level $\alpha=0.05$ and degree of freedom 21 (df=n-1),

Critical t-value for left-tailed test= $t_{\alpha, df}=t_{0.05,21}=- 1.7207$

Decision : Since the test statistic value (0.58) > critical value 1.7207, it means we are failed to reject the null hypothesis .

[Note : When $|t_{cal}|>|t_{cri}|$ , then we accept the null hypothesis.]

Conclusion: We have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

6 0

3 years ago