All categories

3 years ago

Number 6. I have no idea how to do this because the question doesn’t give enough information

Mathematics

1 answer:

Savatey [412]3 years ago

3 0

${13}^{2} = {5}^{2} \times {b}^{2} \\ 169 = 25 \times {b}^{2} \\ 165 - 25 = {b}^{2} \\ 144 = {b}^{2} \\ \sqrt{ {b}^{2} } = \sqrt{144} \\ b = 12$

You might be interested in

The amount of soft drink in a bottle is a Normal random variable. Suppose that in 7% of the bottles containing this soft drink t

WITCHER [35]

Answer:

The mean is 15.93 ounces and the standard deviation is 0.29 ounces.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

7% of the bottles containing this soft drink there are less than 15.5 ounces

This means that when X = 15.5, Z has a pvalue of 0.07. So when X = 15.5, Z = -1.475.

$Z = \frac{X - \mu}{\sigma}$

$-1.475 = \frac{15.5 - \mu}{\sigma}$

$15.5 - \mu = -1.475\sigma$

$\mu = 15.5 + 1.475\sigma$

10% of them there are more than 16.3 ounces.

This means that when X = 16.3, Z has a pvalue of 1-0.1 = 0.9. So when X = 16.3, Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{16.3 - \mu}{\sigma}$

$16.3 - \mu = 1.28\sigma$

$\mu = 16.3 – 1.28\sigma$

From above

$\mu = 15.5 + 1.475\sigma$

$15.5 + 1.475\sigma = 16.3 – 1.28\sigma$

$2.755\sigma = 0.8$

$\sigma = \frac{0.8}{2.755}$

$\sigma = 0.29$

The mean is

$\mu = 15.5 + 1.475\sigma = 15.5 + 1.475*0.29 = 15.93$

The mean is 15.93 ounces and the standard deviation is 0.29 ounces.

6 0

3 years ago

The buying rate and selling rate of a Australian dollar in a bank are rs 80.20and rs 81.40respectively how much Australian dolla

olya-2409 [2.1K]

Answer:

5000 Australian Dollars

Step-by-step explanation:

To find out how many Australian dollars need to be sold, we first need to find the profit of a single dollar sold.

We will be using the formula for profit, which is:

Profit = Total Revenue - Total Cost

Now we define the available variables.

Total Revenue = 81.40

Total Cost = 80.20

Profit = 81.40 - 80.20

Profit = rs 1.20/dollar

Now we have to find how many dollars we have to sell to get a profit of rs 6000.

We simply divide the amount of profit that we want to the price per dollar.

Total Profit = 6000

Profit per dollar = 1.20

This give us:

6000 / 1.20 = 5000 Australian Dollars.

4 0

3 years ago

3. In a single growing season at the Smith Family Orchard, the average yield per apple tree is 150 apples when the number of tre

g100num [7]

Answer:

A.10000

B.25 more trees must be planted

Step-by-step explanation:

⇒Given:

The intial average yield per acre $y_{i}$ = 150

The initial number of trees per acre $t_{i}$ = 100

For each additional tree over 100, the average yield per tree decreases by 1 i.e , if the number trees become 101 , the avg yield becomes 149.
Total yield = (number of trees per acre) $*$ (average yield per acre)