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malfutka [58]
3 years ago
6

Evaluate 5(6) -c ifc=7

Mathematics
2 answers:
zmey [24]3 years ago
8 0

Answer:

The answer should be 23.

Step-by-step explanation:

If C=7, then you just need to plug 7 into the equation.

5(6) - 7

From there, you just need to multiply 5 times 6 which is 30. After that you have 30-7 which gets you 23.

ahrayia [7]3 years ago
5 0
23.

Work:
5(6)-7
5(6)=30
30-7=23
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4 0
2 years ago
5 % of 170 is what number?​
Darina [25.2K]

Answer: 3400

Step-by-step explanation:

We have, 5% × x = 170

or,  

5

100

× x = 170

Multiplying both sides by 100 and dividing both sides by 5,

we have x = 170 ×  

100

5

x = 3400

If you are using a calculator, simply enter 170×100÷5, which will give you the answer.

4 0
2 years ago
Read 2 more answers
What is the product of (x+9)(x-9)
Verdich [7]

Answer:

x^2 - 81

Step-by-step explanation:

There is a formula called the difference of squares, which is

(a+b)(a-b) = a^2 - b^2

8 0
3 years ago
Read 2 more answers
Five cupcakes and two cookies cost $19.75. Two cupcakes and four cookies cost $ 17.50.
alina1380 [7]

Answer:

Step-by-step explanation:

Let x and y represent the cost of a cupcake and cookie respectively.

Given that;

Five cupcakes and two cookies cost  $19.75.

5x+2y=19.75 ---------- 1

Two cupcakes  and four cookies cost $17.50.

2x+4y=17.50 --------------2

Let's solve the simultaneous equation by elimination;

Multiply equation 1 by 2;

10x+4y=39.50-------3\\

Subtract equation 2 from equation 3;

10x-2x+4y-4y=39.50-8x=22

8x=22

divide both sides by 8

\frac{8x}{8} =\frac{22}{8} \\x=2.75

Since we have the value of x, let substitute into equation 1 to get y;

5x+2y=19.75\\5(2.75)+2y=19.75\\13.75+2y=19.75\\2y=19.75-13.75\\2y=6\\y=\frac{6}{2} \\y=3.00

therefore , the cost of cupcakes and cookies are;

cupcakes=  2.75\\cookies= 3.00

PLEASE MARK ME AS BRAINLIEST

6 0
2 years ago
X^2+2x-5=0 quadratic form
julsineya [31]

Answer:

-1+√6

-1-√6

Step-by-step explanation:

x²+2x-5=0

x=(-2±√(2²-4(-5)))/2=(-2±√(4+20))/2=(-2±√24)/2

x₁=(-2+√24)/2 or x₂=(-2-√24)/2

x₁=(-2+2√6)/2 or (-2-2√6)/2

x₁=-1+√6 or x₂=-1-√6

3 0
3 years ago
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