Easy
y=a(x-h)^2+k
vertex is (h,k)
we know that vertex is (4,0)
input that point for (h,k)
y=a(x-4)^2+0
y=a(x-4)^2
passes thorugh the point (6,1)
input that point to find a
1=a(6-4)^2
1=a(2)^2
1=a(4)
divide both sides by 4
1/4=a
thefor the equation is
y=(1/4)(x-4)^2
or
y=(1/4)x^2-2x+4
Answer:
<em><u>The</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u>,</u></em><em><u> </u></em><em><u>q</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>16</u></em><em><u>.</u></em>
Step-by-step explanation:
1) Divide both sides by 3.

2) Simplify 27/3 to 9.

3) Add 7 to both sides.

4) Simplify 9 + 7 to 16.

<em><u>Therefor</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>q</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>16</u></em><em><u>.</u></em>
Answer:
(0,0), (1,1), (2,2)
Step-by-step explanation:
When testing to find possible points in situations like this, I always start by testing with the origin point (0,0).
In this case:
4x+6y<24 ==> 0 + 0 < 24 TRUE, it satisfies the inequality.
We then try with (1,1):
4x+6y<24 ==> 4 + 6 < 24 TRUE, it satisfies the inequality.
And with (2,2):
4x+6y<24 ==> 8 + 12 < 24 TRUE, it satisfies the inequality.
Five Millon four thousand and three hundred