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3 years ago

How do you Find the acute Angle A when sinA=0.616?

Mathematics

1 answer:

kirill [66]3 years ago

4 0

Answer:

arcsin0.616

Step-by-step explanation:

arcsino.616

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What is the solution to this system of equations? 2t + w = 10 4t = 20 − 2w A. It has no solution. B. It has infinite solutions.

joja [24]

Answer:

<h3>B. It has infinite solutions</h3>

Step-by-step explanation:

Given the system of equations:

2t + w = 10 ..... 1

4t = 20 − 2w ... 2

From 1:

w = 10-2t ...3

Substitute 3 into 2 to have;

4t = 20 - 2(10-2t)

4t = 20-20+4t

4t = 4t

Let t = k

Substitute t = k into 1 and get w;

From 1: 2t + w = 10

2k + w =10

w = 10 - 2k

<em>k can take any integers. This shows that the solution to the equation is infinite</em>

7 0

3 years ago

Write the explicit formula for the geometric sequence.

Savatey [412]

This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by 4 gives the next term. In other words:

an = a1 * r ^ (n-1)

Now, knowing that a1 = 2, and r = 4

We check

a2 = 2 * 4 ^ (2-1) = 2 * (4 ^ 1) = 8

a3 = 2 * 4 ^ (3-1) = 2 * (4 ^ 2) = 32

a4 = 2 * 4 ^ (4-1) = 2 * (4 ^ 3) = 128

Therefore, this is the geometric function that this sequence fulfills.

5 0

4 years ago

The sum of 30 times (1/3)^(n-1) from 1 to infinity

sergeinik [125]

Let

$S_n=\displaystyle1+\frac13+\frac1{3^2}+\cdots+\frac1{3^n}$

Then

$\dfrac13S_n=\displaystyle\frac13+\frac1{3^2}+\frac1{3^3}+\cdots+\frac1{3^{n+1}}$

and

$S_n-\dfrac13S_n=\dfrac23S_n=1-\dfrac1{3^{n+1}}\implies S_n=\dfrac32-\dfrac1{2\cdot3^n}$

and as $n\to\infty$ , we end up with

$\displaystyle\lim_{n\to\infty}S_n=\lim_{n\to\infty}\sum_{i=1}^{n+1}\frac1{3^{i-1}}=\lim_{n\to\infty}\left(\frac32-\frac1{2\cdot3^n}\right)=\frac32$

So we have

$\displaystyle\sum_{n=1}^\infty30\left(\frac13\right)^{n-1}=30\cdot\frac32=45$

8 0

3 years ago

The expression, involving exponents , to represent the shaded area, in square inches, diagram. Then use that expression to calcu

mart [117]

Answer:

The shaded area is $23\ in^{2}$

Step-by-step explanation:

we know that

The shaded area is equal to the area of the large square minus the area of the two smaller squares

$A=6^{2} -(3^{2} +2^{2})\\ \\ A=(2*3)^{2} -(3^{2} +2^{2})\\ \\A=(2^{2})(3^{2}) -(3^{2} +2^{2})$

Calculate the shaded area

Remember that

$3^{2}=9\\ 2^{2}=4$

substitute

$A=(4)(9) -(9 +4)\\ \\A=36-13\\ \\A=23\ in^{2}$

5 0

3 years ago

You buy a 1:1000 scale model of the Statue of Liberty during a trip to New York City. The height of the model is 9.3 centimeters

luda_lava [24]

Scale is 1:1000
Thus 9.3cm the actual is 9.3×1000= 9300cm = 93m

8 0

3 years ago