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Nikolay [14]
3 years ago
10

Which equation shows this formula solved for m?

Mathematics
1 answer:
kozerog [31]3 years ago
5 0

Answer:

viariables

Step-by-step explanation:

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Sasha can mow 3/8 of an acre of grass in 45minutes.how many acres of grass does Sasha now per hour?
horrorfan [7]
Keeping in mind that an hour is 60 minutes.

\bf \begin{array}{ccll}
\stackrel{acre}{grass}&\stackrel{minutes}{time}\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
\frac{3}{8}&45\\
g&60
\end{array}\implies \cfrac{\frac{3}{8}}{g}=\cfrac{45}{60}\implies \cfrac{\frac{3}{8}}{\frac{g}{1}}=\cfrac{45}{60}\implies \cfrac{3}{8}\cdot \cfrac{1}{g}=\cfrac{45}{60}
\\\\\\
\cfrac{3}{8g}=\cfrac{45}{60}\implies 180=360g\implies \cfrac{180}{360}=g\implies \cfrac{1}{2}=g
6 0
3 years ago
In the algebraic expression v+8 the v is considered the what
chubhunter [2.5K]

Answer:

the variable  

Step-by-step explanation:

5 0
3 years ago
We learned in that about 69.7% of 18-20 year olds consumed alcoholic beverages in 2008. We now consider a random sample of fifty
maw [93]

Answer:

(1) The expected number of people who would have consumed alcoholic beverages is 34.9.

(2) The standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3) It is surprising that there were 45 or more people who have consumed alcoholic beverages.

Step-by-step explanation:

Let <em>X</em> = number of adults between 18 to 20 years consumed alcoholic beverages in 2008.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.697.

A random sample of <em>n</em> = 50 adults in the age group 18 - 20 years is selected.

An adult, in the age group 18 - 20 years, consuming alcohol is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 50 and <em>p</em> = 0.697.

The probability mass function of a Binomial random variable <em>X</em> is:

P(X=x)={50\choose x}0.697^{x}(1-0.697)^{50-x};\ x=0,1,2,3...

(1)

Compute the expected value of <em>X</em> as follows:

E(X)=np\\=50\times 0.697\\=34.85\\\approx34.9

Thus, the expected number of people who would have consumed alcoholic beverages is 34.9.

(2)

Compute the standard deviation of <em>X</em> as follows:

SD(X)=\sqrt{np(1-p)}=\sqrt{50\times 0.697\times (1-0.697)}=10.55955\approx10.56

Thus, the standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3)

Compute the probability of <em>X</em> ≥ 45 as follows:

P (<em>X</em> ≥ 45) = P (X = 45) + P (X = 46) + ... + P (X = 50)

                =\sum\limits^{50}_{x=45} {50\choose x}0.697^{x}(1-0.697)^{50-x}\\=0.0005+0.0001+0.00002+0.000003+0+0\\=0.000623\\\approx0.0006

The probability that 45 or more have consumed alcoholic beverages is 0.0006.

An unusual or surprising event is an event that has a very low probability of success, i.e. <em>p</em> < 0.05.

The probability of 45 or more have consumed alcoholic beverages is 0.0006. This probability value is very small.

Thus, it is surprising that there were 45 or more people who have consumed alcoholic beverages.

6 0
3 years ago
Suppose you buy 3 pizzas for a party. Each pizza is cut into 8 slices. Twenty slices are eaten. How many whole pizzas are eaten?
vladimir2022 [97]
2 1/2 pizzas are eaten.
8 0
3 years ago
What is the following sentence written as an expression?" Add the product of 3 and 6 to 4".
N76 [4]
The expression will look like this. (3*6)+4
3 0
4 years ago
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