Her speed was 62.5 miles per hour.
Answer:
m<1 = 118
Step-by-step explanation:
The remote angles theorem states that when one extends one of the sides of a triangle, the sum of the two non-adjacent angles is equal to the measure of the angle between the extension of the side and a side of a triangle. One can apply this theorem here by stating that
(28) + (90) = m<1
Remember, a box around an angle signifies that its measure is (90) degrees.
Solve this problem by performing the operation,
118 = m<1
Answer:
<u><em>F(x)= 5*[
+ (a*b)*
+ a*b*x + C.</em></u>
Step-by-step explanation:
<u><em>First step we aplicate distributive property to the function.</em></u>
<u><em>5*(x+a)*(x+b)= 5*[
+x*b+a*x+a*b]</em></u>
<u><em>5*[
+x*(b+a)+a*b]= f(x), where a, b are constant and a≠b</em></u>
<u><em>integrating we find ⇒∫f(x)*dx= F(x) + C, where C= integration´s constant</em></u>
<u><em>∫^5*[
+x*(a+b)+a*b]*dx, apply integral´s property</em></u>
<u><em>5*[∫
dx+∫(a*b)*x*dx + ∫a*b*dx], resolving the integrals </em></u>
<u><em>5*[
+ (a*b)*
+ a*b*x</em></u>
<u><em>Finally we can write the function F(x)</em></u>
<u><em>F(x)= 5*[
+ (a*b)*
+ a*b*x ]+ C.</em></u>
Answer:
Step-by-step explanation:
You aren't able to figure out an exact number of either footballs or basketballs because you don't have enough information for that, but you do have enough to get an expression for one in terms of the other, which I imagine is the point here. We know that for every 1 basketball sold, we sold 2.5 footballs, so the algebraic expression for that is
1 bball = 2.5 fballs
This gives us the number of bballs in terms of fballs but we want the number of fballs in terms of bballs, so solve that expression for fballs:
1 fball = 1/2.5 bballs
or, in words, for every single football sold, 2/5 of a basketball was sold. Sounds silly, but I think your teacher is trying to get you to figure out how to express one thing in terms of another so you can use the expressions in solving story problems.
:/
Let the number of 250g=0.25 kg jars be x and that of 500g=0.5 kg jams be y;
therefore:
total number of jars ws
x+y=511
x=511-y..........i
total mount kgs was:
0.25x+0.5y=186.5....ii
substituting i in ii
0.25(511-y)+0.5y=186.5
127.75-0.25y+0.5y=186.5
solving for y we get:
0.25y=186.5-127.75
0.25y=58.75
y=58.75/0.25
y=235 jars
and
x=511-x
=511-235
=276
hence we conclude that there was 235 jars with 0.5 kg almond and 276 jars with 0.25 kg almonds