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arlik [135]
3 years ago
15

What is the largest number that can divide 35,50 and 40 exactly? ​

Mathematics
1 answer:
Anastasy [175]3 years ago
8 0

the answer is 5 cuz the gcf of the given numbers is 5

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For which equations below is x = -3 a possible solution? Select three options.
vlabodo [156]

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Step-by-step explanation:

x= -3

0x= -3

0-Ix= -3

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Oxygen is being added to a canister which originally contained 5 cubic feet of the gas at
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The change is negative, since the volume in the final state is smaller than the volume in the initial state. 2.25 We express V for the ideal gas as a function of T , p and n: V (T , p, n) = ... each smooth part of the curve and add the integrals, used up yearly by living organisms, which means that even if the oxygen supply was.

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What are the sum of the two pink angles?
jenyasd209 [6]

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45 degrees

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3 years ago
A store has been selling 100 Blu-ray disc players a week at $600 each. A market survey indicates that for each $40 rebate offere
Sav [38]

Answer:

<em>The rebate should be $220</em>

Step-by-step explanation:

<u>Demand Curve</u>

It's the relationship between price (P) and quantity (Q) demanded a certain product or service.

(a) We need to find the function that relates both magnitudes assuming a linear equation. The equation of a line can be found with the point-point formula:

\displaystyle Q-Q_1=\frac{Q_2-Q_1}{P_2-P_1}(P-P_1)

Two sets of data are given: 100 Blu-ray disc players are sold a week at $600 each. The ordered pair for this condition is (P,Q)=(600,100).

The other point comes from the market survey: The number of units sold will increase by 80 (100+80=180) when the price goes down $40 (600-40=560). The new point is (P,Q)=(560,180)

We set up the equation of the demand

\displaystyle Q-100=\frac{180-100}{560-600}(P-560)

Rearranging

-40Q+4000=80P-44800

Or

80P+40Q=48800

Simplifying

2P+Q=1120

(b) The revenue function is Q times the price

R=Q.P

Solving the equation of the demand for P

\displaystyle P=\frac{1120-Q}{2}

Thus, the revenue is

\displaystyle R=Q\cdot \frac{1120-Q}{2}

\displaystyle R=\frac{1120Q-Q^2}{2}

(c) To find the optimum value of the revenue, we take the derivative of R and equate to 0

\displaystyle R'=\frac{1120-2Q}{2}=560-Q=0

Solving

Q=560 units a week

For which the revenue is

\displaystyle R=\frac{1120(560)-560^2}{2}

R=\$156,800

And the price is

\displaystyle P=\frac{1120-560}{2}=280

P=\$280

The rebate should be $600-$280=$220

4 0
3 years ago
Can you help me with these two problems please?? 35 and 36.
Over [174]
35. You just do 35 * .6 and you get 21 rocks.

36. Multiply 10 yards by 3 to get 30 feet then by 12 to get 360 inches and then divide by 6 to get 60 pieces.
4 0
3 years ago
Read 2 more answers
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