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andriy [413]
3 years ago
8

How many bases does a rectangular prism have? one two three four

Mathematics
2 answers:
kolezko [41]3 years ago
7 0

Answer:

B. two

explanation:

i took the test

hope this helps. have a great day!!

vichka [17]3 years ago
4 0

Question:

How many bases does a rectangular prism have?

Answer:

B ) Two

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Which statement is true?
Crank
The answer is neither because to be complementary they need to equal 90 degrees and to be supplementary the need to equal 180 degrees. The sum of the two angles equals 169 degrees.
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3 years ago
The fence along the length of a ranch measures 4,450.5 meters and the fence along the width of a ranch measures 2,890 meters.
lawyer [7]
Given:Length = 4,450.5 metersWidth = 2,890 meters
1 kilometer = 1,000 meters
Length: 4,450.5 meters * 1km/1,000 meters = 4,450.5 km/1,000 = 4.4505km
Width: 2,890 meters * 1km/1,000 meters = 2,890 km/1,000 = 2.89 km
4.4505 km - 2.89 km = 1.5605 km
The length of the fence is 1.5605 km longer than the width of the fence.

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3 years ago
Max makes and sells posters. The function p(x)= -10x^2 +200x -250, graphed below, indicates how much profit he makes in a month
viktelen [127]
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10                         
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750

Correct answer is C)
</span>
7 0
3 years ago
48 = 3/2y <br> simplify your answer as much as possible
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48 = 1\frac{1}{2}y \\48(\frac{2}{3}) = 1\frac{1}{2}y(\frac{2}{3}) \\32 = y
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Which statements are true of functions? Check all that apply.
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Where the rest of the question?
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