The altitude of a plane is 1200 meters. From a point on the ground, the angle of elevation of an airplane is 25º. What is the di
stance from point P to the airplane, to the nearest tenth of a meter? Explain your answer.
1 answer:
Answer:
2839.4 meters
Step-by-step explanation:
Given that:
Altitude = 1200 m
Using trigonometry :
The distance from point P to the airplane :
Using trigonometric relation :
Sin θ = opposite / hypotenus
Sin θ = altitude / x
Sin θ = 1200 m / x
Sin 25 = 1200 / x
0.4226182 = 1200 / x
x = 1200 / 0.4226182
x = 2839.4423
Distance from P to airplane = 2839.4 meters
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