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Alexeev081 [22]
3 years ago
11

The altitude of a plane is 1200 meters. From a point on the ground, the angle of elevation of an airplane is 25º. What is the di

stance from point P to the airplane, to the nearest tenth of a meter? Explain your answer.
Mathematics
1 answer:
gtnhenbr [62]3 years ago
8 0

Answer:

2839.4 meters

Step-by-step explanation:

Given that:

Altitude = 1200 m

Using trigonometry :

The distance from point P to the airplane :

Using trigonometric relation :

Sin θ = opposite / hypotenus

Sin θ = altitude / x

Sin θ = 1200 m / x

Sin 25 = 1200 / x

0.4226182 = 1200 / x

x = 1200 / 0.4226182

x = 2839.4423

Distance from P to airplane = 2839.4 meters

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a) 34mi

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Solve for g: 4g/14 - 3/7 - g/14 = 3/14
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<span><u><em>Answer:</em></u>
g = 3

<u><em>Explanation:</em></u>
To solve for g, we will need to isolate the g on one side of the equation.
<u>This can be done as follows:</u>
</span>\frac{4g}{14} -  \frac{3}{7} -  \frac{g}{14} =  \frac{3}{14}<span>

<u>1- multiply all terms by 14 to get rid of the fraction:</u>
4g - 6 - g = 3

<u>2- Combine like terms:</u>
4g - g = 3 + 6
3g = 9

<u>3- Isolate the g:</u>
</span>\frac{3g}{3} =  \frac{9}{3}
<span>
g = 3

Hope this helps :)</span>
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3 years ago
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