9 m² n³ is the common factor.
9 m⁴ n^5 - 27 m² n³
9 m² n³(m² n² - 3)
Good luck
Adina did not simply. Before multiplying 5.
To get the number of members between 15 years and 30 years we proceed as follows:
z=(x-μ)/σ
where:
mean,μ=23
standard deviation, σ=4 years
thus
P(15<x<31)
when x=15
P(x<15)
z=(15-23)/4
z=-2
thus
P(x<15)=P(z<-2)=0.0228
when x=31
z=(31-23)/4
z=2
thus
P(x<31)=P(z<2)=0.9772
Hence:
P(15<x<31)=0.9544
hence the number of members between that age was:
0.9544×300
=286.32 people
~285 People
Answer: 285 people
According to the rules of significant figures in counting the number of significant figures when dealing with the measurement, especially when it is scientifically measured, you must consider 2 zeros at the right of the period. For example, in 98.00 there are 4 significant figures
<h3>
Answer:</h3>
5.3
<h3>
Step-by-step explanation:</h3>
The mnemoic SOH CAH TOA reminds you that ...
... Tan = Opposite/Adjacent
... tan(24°) = x/12
Then multiplying by 12 gives ...
... 12·tan(24°) = x = 5.34274 ≈ 5.3