Volume of pyramid:

A - base area
H - height
First count volume of one pyramid:
![V=\dfrac{1}{3} \cdot 3 \cdot 4=4 [\hbox{inch}^3]](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B1%7D%7B3%7D%20%5Ccdot%203%20%5Ccdot%204%3D4%20%5B%5Chbox%7Binch%7D%5E3%5D)
So by using 576 inch^3 you can make 576 : 4 =
144 pyramids
I=k/d^2
4=k/d^2 and 1=k/64 so if we divide the first by the second we get:
4/1=(k/d^2)/(k/64)
4=(k/d^2)*(64/k)
4=64/d^2
d^2=64/4
d^2=16
d=4 meters
Yes it is the same thing ! :)
I think it’s 21:9 I don’t know but I think that would be the answer