Answer:
a. E(x) = 3.730
b. c = 3.8475
c. 0.4308
Step-by-step explanation:
a.
Given
0 x < 3
F(x) = (x-3)/1.13, 3 < x < 4.13
1 x > 4.13
Calculating E(x)
First, we'll calculate the pdf, f(x).
f(x) is the derivative of F(x)
So, if F(x) = (x-3)/1.13
f(x) = F'(x) = 1/1.13, 3 < x < 4.13
E(x) is the integral of xf(x)
xf(x) = x * 1/1.3 = x/1.3
Integrating x/1.3
E(x) = x²/(2*1.13)
E(x) = x²/2.26 , 3 < x < 4.13
E(x) = (4.13²-3²)/2.16
E(x) = 3.730046296296296
E(x) = 3.730 (approximated)
b.
What is the value c such that P(X < c) = 0.75
First, we'll solve F(c)
F(c) = P(x<c)
F(c) = (c-3)/1.13= 0.75
c - 3 = 1.13 * 0.75
c - 3 = 0.8475
c = 3 + 0.8475
c = 3.8475
c.
What is the probability that X falls within 0.28 minutes of its mean?
Here we'll solve for
P(3.73 - 0.28 < X < 3.73 + 0.28)
= F(3.73 + 0.28) - F(3.73 + 0.28)
= 2*0.28/1.3 = 0.430769
= 0.4308 -- Approximated
Subtract negative = add
88 + 35 = 123
The solution is 123
Answer:
(1,-2)
Step-by-step explanation:
Choose any value for x that is in the domain to plug into the equation.
Choose 0 to substitute in for x to find the ordered pair.
(0, -19/6)
Choose 1 to substitute in for x to find the ordered pair.
Remove parentheses.
y= -19/6 + 7(1)/6
Simplify
y=2
Use the
x and y values to form the ordered pair.
(1,−2)
Two angles that add up to 180 is supplementary
Answer:
0.3
Step-by-step explanation:
Given:
Number of small dogs = 18
Number of medium-sized dogs = 12
Number of large dogs = 10
To find: probability that a medium-sized dog will be chosen
Solution:
Probability refers to chances of occurrence of some event.
Probability = number of favourable outcomes/total number of outcomes
Total number of dogs = 18 + 12 + 10 = 40
Number of medium-sized dogs = 12
So,
probability that a medium-sized dog will be chosen = Number of medium-sized dogs/Total number of dogs = 
